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Andrews [41]
2 years ago
11

Calculate the molar mass of each of the following: (a) SnO

Chemistry
1 answer:
Andrei [34K]2 years ago
6 0

The molar mass of SnO is  134.71 g/mol .

Molar mass of SnO is calculated as follows ,

  • Make use of the chemical formula to determine the number of atoms of each element in the compound.
  • Multiply the atomic weight of each element with its number of atoms present in the compound.
  • Add up all and assign unit as grams/mole.

Example : molar mass of SnO = atomic weight of Sn + atomic weight of O

molar mass of SnO =118.71 + 16 = 134.71 g / mol

To learn more about molar mass please click here ,

brainly.com/question/12127540

#SPJ4

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Isopropyl alcohol is mixed with water to produce a 35.0 % (v/v) alcohol solution. How many milliliters of each component are pre
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229.25 mL of isopropyl alcohol

425.75 mL of water

Explanation:

Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.

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volume of  isopropyl alcohol = 0.35 × 655 mL = 229.25 mL

Now, knowing the volume of isopropyl alcohol we can determine the volume of water.

volume of the solution = volume of isopropyl alcohol + volume of water

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The _________ indicates that 70% of the Sun's radiation is contained on Earth and 30% is reflected back into space.
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Is metal rusting a chemical reaction? Yes or no
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How many moles of BaSO4 are formed if 0.5 moles of Na2 SO4 react with 60 g of BaCl2? Na2 SO4 + BaCl2 → BaSO4 + 2NaCl
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<span>the balanced equation for the reaction is as follows
Na</span>₂<span>SO</span>₄<span> + BaCl</span>₂<span> ----> 2NaCl + BaSO</span>₄ 
<span>stoichiometry of Na</span>₂<span>SO</span>₄<span> to BaCl</span>₂<span> is 1:1
first we need to find out which the limiting reactant is
limiting reactant is fully used up in the reaction.
                                                                           
number of Na2So4 moles - 0.5 mol number of BaCl2 moles - 60 g / 208 g/mol = 0.288 mol
since molar ratio is 1:1 equal number of moles of both reactants should react with each other
                                                                         
therefore BaCl2 is the limiting reactant and Na2SO4 is in excess. amount of product formed depends on number of limiting reactant present.
stoichiometry of BaCl</span>₂<span> to BaSO</span>₄<span> is 1:1.
                                                                           
therefore number of BaSO4 moles formed - 0.288 mol</span>
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3 years ago
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