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marishachu [46]
3 years ago
7

How do I solve this? please help and only respond with the answer/work. I will mark BRAINLIEST

Chemistry
1 answer:
Ulleksa [173]3 years ago
4 0

Answer: I think the answer is 2.5 M.

Explanation:  Formula: M = n/v

M= 10 mol / 4L

M= 2.5 M

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The half life of plutonium-239 (239pu, pu-239) is 24,100 years. How much plutonium will remain after 1000 years if the initial a
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The equation is Mr=Mi(1/2)^n

where n is the number of half-lives

Mr is the mass remaining after n half lives

Mi is the initial mass of the sample

To find n, the number of half-lives, divide the total time 1000 by the time of the half-life(24,100)

n=1000/24100=0.0414

So Mr=5x(1/2)^1=2.5 g

The mass remaining is 2.5 g

  • The half life is the time in which the concentration of a substance decreases to half of the initial value.

Learn more about half life at:

brainly.com/question/24710827

#SPJ4

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