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True [87]
3 years ago
11

Which one of the following combinations cannot function as a buffer solution?

Chemistry
1 answer:
ANEK [815]3 years ago
3 0

Answer:

c.) HNO₃ & NaNO₃

Explanation:

A buffer system has 2 components:

  • A weak acid and its conjugate base or
  • A weak base and its conjugate acid

<em>Which one of the following combinations cannot function as a buffer solution? </em>

<em> a.) HCN & KCN.</em> YES. HCN is a weak acid and CN⁻ (coming from KCN)  its conjugate base.

<em> b.) NH₃ & (NH₄)₂SO₄.</em> YES. NH₃ is a weak base and NH₄⁺ (coming from (NH₄)₂SO₄) its conjugate acid.

<em> c.) HNO₃ & NaNO₃.</em> NO. HNO₃ is a strong acid.

<em>d.) HF & NaF.</em> YES. HF is a weak acid and F⁻ (coming from NaF)  its conjugate base.

<em> e.) HNO₂ & NaNO₂.</em> YES. HNO₂ is a weak acid and NO₂⁻ (coming from NaNO₂)  its conjugate base.

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Enter your answer in the provided box.
nexus9112 [7]

Answer:

V₂ = 50.93 L

Explanation:

Initial volume, V_1=43.1\ L

Initial temperature, T_1=24^{\circ} C=24+273=297\ K

Final temperature, T_2=78^{\circ} C=78+273=351\ K

We need to find the final volume of the gas. The relation between the volume and the temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{43.1\times 351}{297}\\\\V_2=50.93\ L

So, the final volume of the gas is 50.93 L.

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nexus9112 [7]
It is the 21st amendment
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Answer:

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Explanation:

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3 years ago
Determine the number of moles of C5H12 that are contained in 357.4 g of the compound.
AlladinOne [14]

Answer: 4.96 moles

Explanation:

C5H12 is the chemical formula for pentane, the fifth member of the alkane family.

Given that,

number of moles of C5H12 = ?

Mass in grams = 357.4 g

Molar mass of C5H12 = ?

To get the molar mass of C5H12, use the atomic mass of carbon = 12g; and Hydrogen = 1g

i.e C5H12 = (12 x 5) + (1 x 12)

= 60g + 12g

= 72g/mol

Now, apply the formula

Number of moles = Mass / molar mass

Number of moles = 357.4g / 72g/mol

= 4.96 moles

Thus, 4.96 moles of C5H12 that are contained in 357.4 g of the compound.

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Answer:

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Explanation:

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