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2 years ago

Which one of the following combinations cannot function as a buffer solution?

Chemistry

1 answer:

ANEK [815]2 years ago

3 0

Answer:

c.) HNO₃ & NaNO₃

Explanation:

A buffer system has 2 components:

A weak acid and its conjugate base or
A weak base and its conjugate acid

Which one of the following combinations cannot function as a buffer solution?

a.) HCN & KCN. YES. HCN is a weak acid and CN⁻ (coming from KCN) its conjugate base.

b.) NH₃ & (NH₄)₂SO₄. YES. NH₃ is a weak base and NH₄⁺ (coming from (NH₄)₂SO₄) its conjugate acid.

c.) HNO₃ & NaNO₃. NO. HNO₃ is a strong acid.

d.) HF & NaF. YES. HF is a weak acid and F⁻ (coming from NaF) its conjugate base.

e.) HNO₂ & NaNO₂. YES. HNO₂ is a weak acid and NO₂⁻ (coming from NaNO₂) its conjugate base.

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How many liquids are found on the periodic table? 1

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There are six liquids found on the periodic table.

1. Bromine

2. Mercury

3. Caesium

4. Gallium

5. Rubidium

6. Francium

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3 years ago

______ have no definite shape, but definite volume

NemiM [27]

Answer:

liquids

Explaination:

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3 years ago

The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g

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Answer:

1) When 6.97 grams of sodium(s) react with excess water(l), 56.0 kJ of energy are evolved.

2) When 10.4 grams of carbon monoxide(g) react with excess water(l), 1.04 kJ of energy are absorbed.

Explanation:

1) The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g).

2 Na(s) + 2H₂O(l) ⇒ 2NaOH(aq) + H₂(g) ΔH = -369 kJ

The enthalpy of the reaction is negative, which means that 369 kJ of energy are evolved per 2 moles of sodium. The energy evolved for 6.97 g of Na (molar mass 22.98 g/mol) is:

$6.97g.\frac{1mol}{22.98g} .\frac{-369kJ}{2mol} =-56.0kJ$

2) The following thermochemical equation is for the reaction of carbon monoxide(g) with water(l) to form carbon dioxide(g) and hydrogen(g).

CO(g) + H₂O(l) ⇒ CO₂(g) + H₂(g) ΔH = 2.80 kJ

The enthalpy of the reaction is positive, which means that 2.80 kJ of energy are absorbed per mole of carbon monoxide. The energy evolved for 10.4 g of CO (molar mass 28.01 g/mol) is:

$10.4g.\frac{1mol}{28.01g} .\frac{2.80kJ}{mol} =1.04kJ$

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3 years ago

A gas mixture contains 0.700 mol of N2, 0.300 mol of H2, and 0.400 mol of CH4. Calculate the pressure of the gas mixture and the

Nitella [24]

Answer:

Pressure of the gas mixture: 4.30 atm

Partial pressure N₂ = 2.15 atm

Partial pressure H₂ = 0.91 atm

Partial pressure CH₄ = 1.23 atm

Explanation:

To determine partial pressure we sum the total moles in order to find out the total pressure

We can work with mole fraction

We apply the Ideal Gases Law

0.700 N₂ + 0.300 H₂ + 0.400 CH₄ = 1.4 moles

We replace data → P . V = n . R .T

T° must be at K → 27 °C + 273 = 300 K

P . 8 L = 1.4 mol . 0.082 L.atm/mol.K . 300 K

P = ( 1.4 mol . 0.082 L.atm/mol.K . 300 K) / 8 L = 4.30 atm (Total pressure)

We apply the mol the fraction for the partial pressure

Moles x gas / total moles = partial pressure x gas / total pressure

Mole fraction N₂ → 0.700 /1.4 = 0.5

Partial pressure N₂ = 0.5 . 4.30 atm =2.15 atm

Mole fraction H₂ → 0.300 / 1.4 = 0.21

Partial pressure H₂ = 0.21 . 4.30 atm = 0.91 atm

Mole fraction CH₄ → 0.400 /1.4 = 0.28

Partial pressure CH₄ = 0.28 . 4.30 atm =1.23 atm

7 0

3 years ago

Read 2 more answers

A mixture of helium, nitrogen and oxygen has a total pressure of 821 mmHg. The partial pressure of helium is 105 mmHg, and the p

skad [1K]

Answer:

Total partial pressure, Pt = 821 mm Hg

Partial pressure of Helium, P1 = 105 mm Hg

Partial pressure of Nitrogen, P2 = 312 mm Hg

Partial pressure of Oxygen, P3 = ? mm Hg

According to Dalton's law of Partial pressures,

Pt = P1 + P2 + P3

So, P3 = 404 mm Hg

4 0

2 years ago