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Vlad1618 [11]
3 years ago
12

Identify the products in the following chemical reaction: Multiply chose

Chemistry
1 answer:
rewona [7]3 years ago
7 0

Answer:

C. CaCO3

D. CO2

E. NaCl

. H2O

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Man's scientific theories are often in correct because his knowledge is​
Alik [6]

Answer:

Incomplete  

Explanation:

I wouldn't say that a scientific theory is wrong.

It is the best we have at the time, based on all available knowledge .

As each new discovery is made, scientists modify the theory to fit the new knowledge.

The scientific method is a never-ending process.

8 0
3 years ago
What is the chemical name of the compound K2504?
12345 [234]

Answer:

Potassium sulfate

Explanation:

I searched it up on the internet

Can I please have a brainliest

6 0
3 years ago
Please help.<br><br> Why does the temperature change when a powder is dissolved in water?
Schach [20]

Answer:

In order for the powder to dissolve, each powder molecule must separate from the other powder molecules and be surrounded by water molecules. This shift in arrangement either absorbs or releases energy depending on the situation. It is due to the exchange of energy that the temperature of the solution fluctuates.

Explanation:

:)

5 0
3 years ago
The decomposition of nitrogen dioxide is described by the following chemical equation: Suppose a two-step mechanism is proposed
Mandarinka [93]

Answer:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

Explanation:

<u>first step </u>

NO2(g)  ------------------------------------> NO(g) + O(g)

<u>second step</u>

NO2(g) + O(g) -----------------------------> NO(g) + O2(g)

8 0
3 years ago
A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±
Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0
3 years ago
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