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3 years ago

Subtract 4a-7ab+3b+12 from 12a-9ab+5b-3

Mathematics

2 answers:

Tamiku [17]3 years ago

6 0

Answer:

8a - 2ab + 2b - 15

Step-by-step explanation:

(12a - 9ab + 5b - 3) - (4a - 7ab + 3b + 12)

(12a - 9ab + 5b - 3) - 4a + 7ab - 3b - 12

12a - 4a - 9ab + 7ab + 5b - 3b - 3 - 12

8a - 2ab + 2b - 15

viktelen [127]3 years ago

6 0

Answer:

8a - 2ab + 2b - 15

Step-by-step explanation:

12a-4a - 9ab--7ab + 5b-3b - 3-12

8a-2ab + 2b - 15

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Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

Find the equation of a line with m = 3 that passes though the point (-12,<br> 4).

Viefleur [7K]

Answer:

y = 3x + 40

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 3 , then

y = 3x + c ← is the partial equation

To find c substitute (- 12, 4 ) into the partial equation

4 = - 36 + c ⇒ c = 4 + 36 = 40

y = 3x + 40 ← equation of line

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3 years ago

Translate the equation mat at right into an equation. remember that the duble line represent equals

Jobisdone [24]

Answer:

translate the equation mat at right into an equation. remember that the duble line represent equals

Step-by-step explanation:

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4 years ago

Help I need to know I only have 15 min <br> What does x equal in x/2=-5

SSSSS [86.1K]

Answer:

x= -10

Step-by-step explanation:

Brainliest please? :)

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3 years ago

What is the measure of angle k?

Murljashka [212]

9514 1404 393

Answer:

59°

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

∠N +∠L = 180°

(a +16) +(a -18) = 180

2a = 182 . . . . . . . . . . add 2

a = 91 . . . . . . . . . . . . divide by 2

Then the measure of angle M is ...

∠M = (a+30)° = (91 +30)° = 121°

and angle K is its supplement.

∠K = 180° -121°

∠K = 59°

8 0

3 years ago

Subtract 4a-7ab+3b+12 from 12a-9ab+5b-3​

Subtract 4a-7ab+3b+12 from 12a-9ab+5b-3