Answer:
32
Step-by-step explanation:
So, lets go over what we know:
The equation to find x is the same on both sides.
Now, lets find this equation:
So, the total area of the two lines on the left side of the triangle are 24.
Lets first subtract the first line from the total of the two lines to find the value of the second line:
24-3
=
21.
Now that we know the value of the 2nd line is 21. lets divide it by the first line(3) to find the scale factor:
21/3
=
7
So the scale factor is 7!
Lets plug this in for x.
We know that the first line is 4.
The second line is 7x bigger than 4.
So we can calculate this as:
7x4
=
28
So x is 28!
This is your answer!
Hope it helps! :)
Answer:
length = 14 m
width = 7 m
Step-by-step explanation:
l = length
w = width
l = 2w - 8
w(2w - 8) = 42
2w² - 8w - 42 = 0
you can factor out a 2 to work with smaller numbers:
w² - 4w - 21 = 0
(w - 7)(w + 3) = 0
w = 7
'w' cannot equal a negative so we discount it as an answer
find length:
l = 2(7) - 8
l = 14 - 8 or 6m
-25/12
You have to change the denominator the the least common multiple then multiply the numerator by the number you multiplied it’s denominator with.
<em><u>16/4+12 ? 24/2</u></em>
<em><u>4+12 ? 12</u></em>
<em><u>16 ? 12</u></em>
<em><u>?=></u></em>
<em><u>ANSWER: A - ></u></em>
Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,
which is a cubic polynomial in 
with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,
where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then 
can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)
