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faust18 [17]
3 years ago
12

How do forces affect a body's motion?

Physics
1 answer:
natali 33 [55]3 years ago
8 0
By putting to much weight on it our body causing it to hurt or fall hope this helps
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A Yugo can accelerate from rest to a speed of 28 m/s in 20 s. What is the average acceleration of the car? What distance does it
harina [27]

Answer:

Explanation:

a=28/20

a=1.4 m/s²

V²=v0²+2a.D

28²=0+2x1.4D

784 = 2.8D

D = 280 m

6 0
3 years ago
An insulated box has a barrier that confines a gas to only one side of the box. The barrier springs a leak, allowing the gas to
Vilka [71]

Answer:

B) The entropy is greater in the second state, with the gas on both sides of the box.

Explanation:

As we know that ,this is a irreversible process .The process leaves some effect on the surrounding or on the system itself ,is known as irreversible process.But on the other hand those process does not leave any effect on the system and surrounding is known as reversible process.

The entropy in the irreversible process always increases ,that is why the the entropy will be more when gas occupy the both boxes.

Therefore the answer is --B

3 0
3 years ago
If the period of a pendulum were 2.4 s on the moon, which has an acceleration due to gravity of 1.67 m/s^2, then how long would
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5 0
3 years ago
Sort the processes based on the type of energy transfer they involve.??
klemol [59]
The 1st one goes two added sodoes the second one then the third goes to removed then the fourth goes to added and the rest go to removed
3 0
3 years ago
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Explanation A 5000 kg rocket is at rest in deep space. The rocket burns fuel pushing 10kg of exhaust gases rearward at 4000 m/s.
katovenus [111]

Answer:

F = 4000 N

Explanation:

given,

mass of rocket (M)= 5000 Kg

10 Kg gas burns at speed (m)= 4000 m/s

time = 10 s

average force = ?

at the end the rocket is at rest

by conservation of momentum

 M v + m v' = 0

 5000 x v - 10 x 4000 = 0

 5000 v = 40000

    v = 8 m/s

speed of rocket = 8 m/s

now,

we know

change in momentum = F x Δ t

F = \dfrac{m(v_i-v_f)}{\Delta t}

F = \dfrac{5000(8-0)}{10}

      F = 4000 N

Hence, the average force applied to the rocket is equal to F = 4000 N

4 0
3 years ago
Read 2 more answers
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