2 years ago

A wave has a frequency of 46 Hz and a wavelength of 1.7 meters. What is the speed of the wave?

Physics

1 answer:

olga55 [171]2 years ago

7 0

Answer:0.588..

Explanation:

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Two force vectors are oriented such that the angle between their directions is 38 degrees and they have the same magnitude. If t

Usimov [2.4K]

Answer:

Sum of the forces will be equal to 3.479 N

Explanation:

We have given two same forces are oriented at an angle of 38°

Magnitude of each force is given $F_1=F_2=1.84$

We have to find the sum of the forces

Sum of the forces will be equal to

$F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\Theta }$

So sum of the forces will be equal to $F=\sqrt{1.84^2+1.84^2+2\times 1.84\times 1.84\times cos38^{\circ} }=3.479$

So sum of the force will be equal to 3.479 N

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2 years ago

Measurements of two electric currents are shown in the chart. A 3-column table with 2 rows titled Electric Currents. The first c

Jobisdone [24]

The answer is B - Current Y has a greater potential difference, and the charges flow at a slower rate.

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3 years ago

Read 2 more answers

1. How can you explain the sound has energy?<br><br><br>

LenKa [72]

Answer:

Sound energy is produced when an object vibrates. The sound vibrations cause waves of pressure that travel through a medium, such as air, water, wood or metal. Sound energy is a form of mechanical energy.

Explanation:

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2 years ago

Three disks are spinning independently on the same axle without friction. Their respective rotational inertias and angular speed

ololo11 [35]

Answer:

3/7 ω

Explanation:

Initial momentum = final momentum

I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet

-Iω + 6Iω - 2Iω = 7I ωnet

3Iω = 7I ωnet

ωnet = 3/7 ω

The final angular velocity will be 3/7 ω counterclockwise.

7 0

3 years ago

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A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string

alexdok [17]

Answer:

$v_{max}=8.2226m/s$

Explanation:

The problem is solved using the law of conservation of energy,

$mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}$

$v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}$

$v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}$

$v_{max}=8.2226m/s$

8 0

2 years ago