Answer:
The magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N
Explanation:
Given;
first object with mass, m₁ = 285 kg
second object with mass, m₂ = 585 kg
distance between the two objects, r = 4.3 m
The midpoint between the two objects = r/₂ = 4.3 /2 = 2.15 m
Gravitational force between the first object and the 42 kg object;
where;
G = 6.67 x 10⁻¹¹ Nm²kg⁻²
Gravitational force between the second object and the 42 kg object
Magnitude of net gravitational force exerted on 42kg object;
F = 3.545x 10⁻⁷ N - 1.727 x 10⁻⁷ N
F = 1.818 x 10⁻⁷ N
Therefore, the magnitude of the net gravitational force exerted by these objects on a 42.0-kg object is 1.818 x 10⁻⁷ N
The force on one end of the trough is 5.4 X 10⁵ N
<u>Explanation:</u>
The triangle is equilateral which means all the interior angles are 60° and the sides are 6m long.
According to the figure,
AI / 8 = sin (60) = √3/2
AI = 4√3
The depth of the water is AI = 4√3
The interval becomes, | 0 , 4√3|
w = 2JK
(the hydrostatic force acting on the strip is the product of the pressure and the area)
where.
ρ = 875 kg/m³
g = 9.8m/s²
d = depth ( d = y')
limit is 0 → 4√3
On solving the equation, we get the value of limit as 32√3
Therefore, the force on one end of the trough is 5.4 X 10⁵ N
The resistance of a 2 m long tungsten wire whose cross-sectional area of 0.15 mm² will be 0.74 ohm.
<h3>What is resistance?</h3>
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
ρ is the resistivity of tungsten = 5.6×10⁻⁸ (ohm m)
The relation of resistance with length and thickness is given by ;
Hence, the resistance of tungsten wire will be 0.74 ohm.
To learn more about the resistance, refer to the link;
brainly.com/question/20708652
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Answer:
5. All of the answers are yes.
Explanation:
<h2><u><em>
PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
Answer: 66.7 watts
Explanation:
Given that:
Work performed by man = 200 j
Time taken to do work = 3 seconds.
Power = ?
Recall that power is the rate of work done per unit time
i.e Power = work/time
Power = 200J / 3seconds
Power = 66.7 watts
Thus, his power is 66.7 watts