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Answer:
can someone help me with physics to 
 
        
                    
             
        
        
        
Answer:
44 m
Explanation:
Given that,
Horizontal velocity of the ball, u = 40 m/s
It is 6 m above the level field.
We need to find the distance covered by the ball when move horizontally before striking the ground. Let it is d.
Firstly, we will find time taken for the ball to hit the ground. Using second equation of motion as follows :

Put u = 0 and a = g

No finding the horizontal distance as follows :
d = ut
d = 40 m/s × 1.1 s
d = 44 m
So, the ball will move 44 m horizontally before striking the ground.
 
        
             
        
        
        
<span>Density can be determined by the
mass of an object and how much it takes up space (volume). It is represented by
the formula D = M/V where D is the density in kg/m^3 or lb/ft^3, M is the mass
in kg or lb and V is the volume in m^3 or ft^3. The answer would be A.  For example, you are given the mass of an
object of 40.5kg and a volume of 15m^3. Find its density.</span>
 
D = M/V
D = (40.5 kg)
/ (15 m^3)
<span>D = 27/10 or
2.7 kg/m^3 </span>