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sp2606 [1]
3 years ago
10

A white-blue star is hotter than a red star. true or false

Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
5 0
A white-blue star is indeed hotter than a red star. So True :)
Dafna11 [192]3 years ago
5 0
I believe your answer is true. I hope this helped! 
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A 24 resistor, an inductor with a reactance of 12 , and a capacitor with a reactance of 10 are in series across a 60 V 50 Hz sou
sukhopar [10]

Answer:

A⋅24=24A

12=24A

10=24A

a⋅(60V)⋅(50Hz)=3000aVHz

Explanation:

3 0
3 years ago
The velocity of an object includes its speed and what
SCORPION-xisa [38]
I believe that the correct answer you are looking for is the distance traveled 

5 0
3 years ago
Read 2 more answers
Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 3.56 kg and rotate with
Natali5045456 [20]

Answer:

(a) 3107.98 J

(b) 14530.6 J

Explanation:

mass, m = 3.56 kg

angular speed, ω = 179 rad/s

Moment of inertia of solid cylinder, I = 1/2 mr^2

where, m is the mass and r be the radius of the cylinder.

(a) radius, r = 0.330 m

I = 0.5 x 3.56 x 0.330 x 0.330 = 0.194 kgm^2

The formula for the rotational kinetic energy is given by

K = \frac{1}{2}I\omega ^{2}

K = 0.5 x 0.194 x 179 x 179 = 3107.98 J

(b) radius, r = 0.714 m

I = 0.5 x 3.56 x 0.714 x 0.714 = 0.907 kgm^2

The formula for the rotational kinetic energy is given by

K = \frac{1}{2}I\omega ^{2}

K = 0.5 x 0.907 x 179 x 179 = 14530.6 J

3 0
3 years ago
Which part of the electromagnetic spectrum has a lower frequency than visible light?
miv72 [106K]

Answer:

infrared

Explanation:

Electromagnetic spectrum w.r.t. increasing frequency is

Radio waves

Microwaves

Infra red

visible

ultra violet

x rays

gamma rays

3 0
3 years ago
The Earth's magnetic field is approximately 0.5 Gauss. What is the magnetic energy density of this field
ser-zykov [4K]

Answer:

The  magnetic energy density  is  E_B  =  9.95 *10^{-4} \  J/m^3

Explanation:

From the question we are told that  

    The  earths magnetic field is  B  =  0.5 \  Gauss

Now

          1 \ Gauss  \to  1 *10^{-4} \ T

=>        0.5  \ Gauss  \to  x T

So  

          x =  \frac{0.5 *  1*10^{-4}}{1}

          x = B= 5.0 *10^{-5} \  T

Generally the magnetic energy density is  mathematically represented as

        E_B  =  \frac{B^2}{ 2 *  \mu_o  }

  Here \mu_o is the  permeability of  free space with a constant value

          \mu_o  =  4\pi * 10^{-7} N/A^2

substituting values for equation above  

       E_B  =  \frac{(5*10^{-5})^2}{ 2 *   4\pi * 10^{-7}  }

       E_B  =  9.95 *10^{-4} \  J/m^3

5 0
3 years ago
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