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ASHA 777 [7]
2 years ago
14

Help please you’ll get 18 points to answer this correctly

Chemistry
1 answer:
sergij07 [2.7K]2 years ago
4 0
Sand:
0.0625-2mm
By another definition, in terms of particle size as used by geologists, sand particles range in diameter from 0.0625 mm (or ​1/16 mm) to 2 mm. An individual particle in this range size is termed a sand grain.

Cobble:
64-256 mm
(a) A rock fragment larger than a pebble and smaller than a boulder, having a diameter in the range of 64-256 mm (2.5-10 in., or -6 to -8 phi units) being somewhat rounded or otherwise modified by abrasion in the course of transport; in Great Britain, the range of 60-200 mm has been used.

Silt:
0.002 to 0.05mm
Silt particles are from 0.002 to 0.05 mm in diameter. Sand ranges from 0.05 to 2.0 mm. Particles larger than 2.0 mm are called gravel or stones. Most soils contain a mixture of sand, silt and clay in different proportions.

Boulders:
>256 mm
In geology, a boulder is a rock fragment with size greater than 256 millimetres (10.1 in) in diameter. Smaller pieces are called cobbles and pebbles. While a boulder may be small enough to move or roll manually, others are extremely massive. In common usage, a boulder is too large for a person to move.
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Sort the following chemicals for their ability to act as an oxidizer. List from strongest to weakest; 1 being strongest, 6 being
spin [16.1K]
Answer : If we list the given chemicals according to their increasing oxidising ability then the order will be like this; 1 being the strongest and 6 being the weakest 
1. K > 2. Ca >3. Ni> 4. Cu> 5. Ag> 6.Au

Explanation : Considering the reduction potential of each chemical species it will be easy to identify their oxidising capacity and differentiate accordingly;

More negative the value of reduction potential more is the ability of the chemical species to get oxidised.

Chemicals with their reduction potential is given below.

K has -2.92; Ca has -2.76; Ni has -0.23; Cu has 0.52; Ag has 1.50 and Au has 1.50.


7 0
3 years ago
Read 2 more answers
Determine the volume of water to be added to the nitric acid solution at a concentration of 8.61 mol / L to prepare 500 mL of th
Alex_Xolod [135]

Answer:

398 mL

Explanation:

Using the equation for molarity,

C₁V₁ = C₂V₂ where C₁ = concentration before adding water = 8.61 mol/L and V₁ = volume before adding water, C₂ = concentration after adding water = 1.75 mol/L and V₂ = volume after adding water = 500 mL = 0.5 L

V₂ = V₁ + V' where V' = volume of water added.

So, From C₁V₁ = C₂V₂

V₁ =  C₂V₂/C₁

= 1.75 mol/L × 0.5 L ÷ 8.61 mol/L

= 0.875 mol/8.61 mol/L

= 0.102 L

So, V₂ = V₁ + V'

0.5 L = 0.102 L + V'

V' = 0.5 L - 0.102 L

= 0.398 L

= 398 mL

So, we need to add 398 mL of water to the nitric solution.

6 0
2 years ago
Please help! I need an answer ASAP, I will be marking brainliest.
asambeis [7]
B because A is for radios of course and C is thermal energy and D is radioactive
6 0
3 years ago
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How does changing the volume or temperature of a gas affect the pressure of that gas?
Masja [62]

Answer:

When a gas occupies a smaller volume, it exerts a higher pressure; when it occupies a larger volume, it exerts a lower pressure (assuming the amount of gas and the temperature do not change). Since P and V are inversely proportional, a graph of 1/P vs. V is linear.

Explanation:

<h2><u><em>This is all I know.</em></u></h2><h2><u><em>Hope it helps~</em></u></h2><h2><u><em>Good luck with your work!!~</em></u></h2>
6 0
2 years ago
Instant oxidation will usually result in a(n)
viva [34]

Answer:

A

Explanation:

Oxidation is related to rusting.

6 0
2 years ago
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