According to the Dalton's law of Partial pressure, the pressure of the gas has been the sum of the partial pressure of each gas in the mixture.

<h3 /><h3>Computation for the pressure of gas</h3>

The given gas has partial pressure of Nitrogen, $P_{N_2}=3.5\;\rm atm$

The partial pressure of Oxygen, $P_{O_2}=8\;\rm atm$

The partial pressure of Argon, $P_{Ar}=0.25\;\rm atm$

The partial pressure of Helium, $P_{He}=0.15\;\rm atm$

The total pressure, (<em>P</em>) of the gas has been given as:

$P=P_{N_2}\;+\;P_{O_2}\;+\;P_{Ar}\;+\;P_{He}\\
P=3.5\;+8\;+\;0.25\;+\;0.15\;\text{atm}\\
P=11.9\;\rm atm$

The total pressure of the gas has been 11.9 atm.

Learn more about the vapor pressure, here:

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7 0

3 years ago

Water ionizes by the equationH2O(l)⇌H+(aq)+OH−(aq)The extent of the reaction is small in pure water and dilute aqueous solutions

tia_tia [17]

Explanation:

$H_2O(l)\rightleftharpoons H^+(aq)+OH^-(aq)$

The value of $K_w$ :

$K_w=[H^+][OH^-]$

a. pOH = 3.51

The sum of pH and pOH is equal to 14.

pH + pOH = 14 (at 25°C)

pH = 14 - 3.51 = 10.49

The pH of the solution is defined as negative logarithm of hydrogen ion concentration in solution.

$pH=-\log[H^+]$

$10.49=-\log[H^+]$

$[H^+]=3.2\times 10^{-11}$

$3.2\times 10^{-11} M$ is the $H^+$ concentration for an aqueous solution with pOH = 3.51 at 25°C.

At a certain temperature, the pH of a neutral solution is 7.56.

Neutral solution means that concentration of hydrogen ion and hydroxide ions are equal.

$[H^+]=[OH^-]$

$7.56=-\log[H^+]$

$[H^+]=2.754\times 10^{-8} M$

The value of $K_w$ at at this temperature:

$K_w=[H^+][OH^-]$

$K_w=[H^+][H^+]$

$K_w=(2.754\times 10^{-8})^2=7.6\times 10^{-16}$

The value of $K_w$ at at this temperature is $7.6\times 10^{-16}$ .

5 0

4 years ago

What is the number of moles and the mass of Mg required to react with 7.50g of HCl and produce MgCl2 and H2? 1.25 g 2.50 g 5.00

boyakko [2]

Answer:

The correct option is: 2.50 g

Explanation:

Reaction involved: Mg(s) + 2 HCl(aq) → MgCl₂(aq) + H₂(g)

Molar mass: Mg = 24.305 g/mol, HCl = 36.461 g/mol

In the given reaction, 1 mole Mg reacts with 2 moles HCl.

Given: mass of HCl = 7.50 g

So, the number of moles of HCl = given mass ÷ molar mass = 7.50 g ÷ 36.461 g/mol = 0.2057 moles

Therefore, the<u> number of moles of Mg</u> that reacts with 0.2057 mole HCl = 0.2057 ÷ 2 = 0.1028 moles

Therefore, <u>the mass of Mg in grams</u> = molar mass × number of moles = 24.305 g/mol × 0.1028 mole = 2.5 g

4 0

4 years ago