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Sidana [21]
4 years ago
10

Of the following which is the most concentrated solution

Chemistry
2 answers:
OleMash [197]4 years ago
8 0
A) 12 G/ML should be most concentrated.
Rama09 [41]4 years ago
4 0

I think A. 12 G/ML was the answer

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Is the reaction to produce zinc from zinc sulfide spontaneous under standard conditions? Coupledreaction: ZnS(s) + H2 (g)  Zn(s
finlep [7]

Answer:

The reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.

Explanation:

Hess's law states: "When one reaction can be expressed as the algebraic sum of others, its heat of reaction is equal to the same algebraic sum of the partial heats of the partial reactions". So Hess's Law is an indirect method of calculating the heat of reaction or enthalpy of reaction when the chemical reaction occurs in one or more than one stage.

Taking into account that ΔG is a state function, which only depends on the initial and final states, its variation in a reaction is calculated by adding the free energies of the reactants and products involved in it when both are in the normal state. That is, at the pressure of 1natm if it is gases or at the concentration of 1 mol / L for substances in liquid solution.

The sum of the fitted equations should give the problem equation. So, if in a "data" reaction a substance is as a reactant and in the reaction that you must obtain is as a product, you must turn the "data" reaction and ΔG will change its sign. In this case, this happen with the reaction 1 (Rxn1):

Rxn1: ZnS (s) → Zn (s) + S (s)          ΔG1°= 201.3 kJ

Rxn2: S (s) + H₂ (g) → H₂S (g)        ΔG2°= -33.4kJ

Adding both reactions (taking into account that certain substances appear sometimes as a reagent and others as a product, so they are totally eliminated if they appear in the same quantities) you get:

ZnS (s) + H₂ (g) → Zn (s) + H₂S (g)

Adding algebraically ΔG1° and ΔG2° you get:

ΔG°= ΔG1° + ΔG2°

ΔG°= 201.3 kJ - 33.4 kJ

ΔG°= 167.9 kJ

If a chemical reaction proceeds with a ΔG <0 the process is  spontaneous. If, on the other hand, ΔG> 0, the reaction is not spontaneous.

Since ΔG>0, <u><em>the reaction to produce zinc from zinc sulfide is not spontaneous under standard conditions.</em></u>

6 0
3 years ago
3.5g of a Certain compound X, known to be made of carbon, hydrogen, and perhaps oxygen, and to have a molecular molar mass of 15
shutvik [7]

Answer:

C₅H₁₀O₅

Explanation:

1. Calculate the mass of each element in 2.78 mg of X.

(a) Mass of C

\text{Mass of C} = \text{5.13 g CO}_{2}\times \dfrac{\text{12.01 g C}}{\text{44.01 g }\text{CO}_{2}}= \text{1.400 g C}

(b) Mass of H

\text{Mass of H} = \text{2.10 g H$_{2}$O}\times \dfrac{\text{2.016 g H}}{\text{18.02 g H$_{2}$O}} = \text{0.2349 g H}

(c) Mass of O

Mass of O = 3.5 - 1.400 - 0.2349 = 1.87 g

2. Calculate the moles of each element

\text{Moles of C = 1400  mg C}\times\dfrac{\text{1 mmol C}}{\text{12.01 mg C }} = \text{116.6 mmol C}\\\\\text{Moles of H = 234.9 mg H} \times \dfrac{\text{1 mmol H}}{\text{1.008 mg H}} = \text{233.1 mmol H}\\\\\text{Moles of O = 1870 mg O} \times \dfrac{\text{1 mmol O}}{\text{16.00 mg O}} = \text{116 mmol O}

3. Calculate the molar ratios

Divide all moles by the smallest number of moles.

\text{C: } \dfrac{116.6}{116.6}= 1\\\\\text{H: } \dfrac{233.1}{116.6} = 1.999\\\\\text{O: } \dfrac{116}{116.6} = 1.00

4. Round the ratios to the nearest integer

C:H:O = 1:2:1

5. Write the empirical formula

The empirical formula is CH₂O.

6. Calculate the molecular formula.

EF Mass = (12.01 + 2.016  + 16.00) u  = 30.03 u

The molecular formula is an integral multiple of the empirical formula.

MF = (EF)ₙ

n = \dfrac{\text{MF Mass}}{\text{EF Mass }} = \dfrac{\text{150 u}}{\text{30.03 u}} = 5.00  \approx 5

MF = (CH₂O)₅ = C₅H₁₀O₅

The molecular formula of X is C₅H₁₀O₅.

8 0
4 years ago
In order to change a solid to a liquid or a liquid to a gas, what is needed?
Neporo4naja [7]
Heat; rather, or change of the molecules to make them move faster
6 0
3 years ago
This type of erosion picks up materials and transports them in the air, often causing the abrasion of surfaces.
SVEN [57.7K]

Answer: Sediment Transport by Wind

Explanation: Like flowing water, wind picks up and transports particles. Wind carries particles of different sizes in the same ways that water carries them (Figure below). Tiny particles, such as clay and silt, move by suspension. They hang in the air, sometimes for days.

6 0
3 years ago
Na + H2 → NaCl balanced equation
hodyreva [135]

Answer:

..............

........

.............

6 0
2 years ago
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