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cestrela7 [59]
3 years ago
13

-X + 3= -2What ís the solution to this equation?​

Mathematics
2 answers:
Rzqust [24]3 years ago
8 0
-x+3=-2
-x=-5
x=5
the solution is 5
navik [9.2K]3 years ago
3 0

Answer:

-x = -2 - 3

Step-by-step explanation:

-x = -2 - 3

-x = -5 then make it positive

x = 5

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9+3.5g=11-0.5g brainliest to whoever gives steps
kow [346]

Answer:

The answer is <u>g = 0.5</u>

Step-by-step explanation:

1. Your equation is :

<em>9+3.5g=11-0.5g</em>

2. First, multiply both sides by ten

<em>9 * 10 + 3.5 * 10 = 11 * 10 - 0.5 * 10</em>

3. Next we refine the equation

<em>90 + 35g = 110 - 5g</em>

4. Now, lets subtract 90 from both sides

<em>90 + 35g - 90 = 110 - 5g - 90</em>

5. Simplify

<em>35g + 5g = -5g + 20 + 5g</em>

6. We then add 5g to both sides

<em>35g + 5g = -5g + 20 + 5g</em>

7. Simplify again

<em>40g = 20</em>

8. Now, divide both sides by 40

<em>40g/40 = 20/40</em>

9. And finally, simplify once again to get your final answer.

<em>g = 1/2 or 0.5</em>

I hope this helped :)

7 0
3 years ago
Find the pattern of 1,2,6,18 and state if its arithmetic or geometric
Gnesinka [82]

Answer:

 its a geometric sequence where each term is 3 times the previous term.

Step-by-step explanation:

{2,6,18,54,162,486,1458...}

6 0
2 years ago
80 times 1.5 that’s all
Evgesh-ka [11]
What?



explanation: ..
5 0
3 years ago
Read 2 more answers
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
Help me please and thank you<br> Can you show the work
faust18 [17]

Answer:

the answer is c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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