The mass of the block is 920 kg.
The angle of inclination of the slope with respect to the plane is 30 degree.
The initial speed of the block [u] =50 cm/s
=50×0.01 m/s
=0.5 m/s
The block is once pushed and it moves downward on the slope. The distance of the block from the bottom is 2.3 m .
Hence the distance travelled by the block [s]=2.3 m
We are asked to calculate the final velocity of the block when it touches the ground.
First we have to calculate the acceleration of the block.
Resolving g into horizontal and vertical component we get,
![[1] gsin\theta\ is\ along\ the\ slope\ and\ downward](https://tex.z-dn.net/?f=%5B1%5D%20gsin%5Ctheta%5C%20is%5C%20along%5C%20the%5C%20slope%5C%20and%5C%20downward)
![[2] gcos\theta\ is\ along\ the\ normal\ drawn\ to\ the\ block](https://tex.z-dn.net/?f=%5B2%5D%20gcos%5Ctheta%5C%20is%5C%20along%5C%20the%5C%20normal%5C%20drawn%5C%20to%5C%20the%5C%20block)
Now putting the equation of kinematics we get-

Here v is called final velocity and a is the acceleration.
![=[0.5]^2+2*gsin\theta *2.3](https://tex.z-dn.net/?f=%3D%5B0.5%5D%5E2%2B2%2Agsin%5Ctheta%20%2A2.3)
[sin30=0.5]


[ans]
Answer:
That's about 12 kilometers per hour faster than the average female professional tennis player.
Explanation:
Newton observed the action of a prism on the white light and on red light. Because he did not control the event, this investigation of light was an observational study.
Hope this helps! (:
A developing story hope it helped