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3 years ago

Explain step by step

Physics

1 answer:

Eduardwww [97]3 years ago

3 0

I think it is 3 but I know it may be wrong.

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A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula

Maru [420]

Answer:

<h3>The answer is 198.23 kg</h3>

Explanation:

To find the mass of an object given it's mass and acceleration we use the formula

$m = \frac{f}{a} \\$

where

m is the mass

F is the force

a is the acceleration

From the question

a = 92.54 m/s²

F = 18,344 N

We have

$m = \frac{18344}{92.54} \\ = 198.2277933...$

We have the final answer as

Hope this helps you

4 0

4 years ago

Read 2 more answers

The unit of energy is a derived unit give reasons.<br>

liraira [26]

Answer:

ioinl

Explanation:

6 0

2 years ago

Let r denote the distance between the center of the earth and the center of the moon. What is the magnitude of the acceleration

stepan [7]

Answer:

The magnitude of the acceleration ae of the earth due to the gravitational pull of the moon is $\mathbf{3.3187\times10^{-5}}\frac{m}{s^{2}}$

Explanation:

By Newton's gravitational law, the magnitude of the gravitational force between two objects is:

$F=G\frac{Mm}{r^{2}}$ (1)

With G the gravitational constant, M the mass of earth, m the mass of the moon and r the distance between the moon and the earth, a quick search on physics books or internet websites give us the values:

$M=5.972\times10^{24}\,kg$

$m=7.34767309\times10^{22}\,kg$

$r=384400\,km$

$G=6.674\times10^{-11}\,\frac{N\,m^{3}}{kg^{2}}$

Using those values on (1)

$F=(6.674\times10^{-11})*\frac{(5.972\times10^{24})(7.34767309\times10^{22})}{(384400\times10^{3})^{2}}$

$F\approx1.98193\times10^{20}N$

Now, by Newton's second Law we can find the acceleration of earth ae due moon's pull:

$F=M*ae\Longrightarrow ae=\frac{F}{M}=\frac{1.98193\times10^{20}}{5.972\times10^{24}}\approx\mathbf{3.3187\times10^{-5}}$

6 0

4 years ago

During a laboratory experiment, the temperature of the gas in a balloon is varied and the

lys-0071 [83]

A. The IV is the temperature of gas in the balloon.

B. The DV is the volume of the balloon.

This is because the temperature of the gas is the variable being manipulated in the experiment (Independent) and the volume is changing based on the shifts of the temperature (thus volume is Dependent).

4 0

3 years ago

Please help. Having a hard time figuring out

Goryan [66]

Yeah that’s is correct

5 0

3 years ago