Answer:
500 m
Explanation:
t = Time taken
u = Initial velocity = 50 m/s
v = Final velocity = 0
s = Displacement
a = Acceleration = -2.5 m/s²
Equation of motion
Time taken by the train to stop is 20 seconds
∴ The engineer applied the brakes 500 m from the station
Answer:
The average power of the engine of the sports car is 56.32 kW
Explanation:
Given;
mass of the sports car, m = 1100 kg
initial velocity of the sports car, u = 0 m/s
final velocity of the sports car, v = 32 m/s
time of motion, t = 10 s
The kinetic energy of the car is given by;
K.E = ¹/₂m(v² - u²)
K.E = ¹/₂mv²
K.E = ¹/₂ x 1100 x 32²
K.E = 563200 J
The average power of the engine of the sports car is given by;
Pavg = Energy / time
Pavg = 563200 / 10
Pavg = 56320 W
Pavg = 56.32 kW
Therefore, the average power of the engine of the sports car is 56.32 kW
Resistors tell me if im right
The answer is “increasing wavelength near beach”
The answer is B, because all energy is released at once in static electricity.
There’s a quizlet that mentions these questions, if you are having trouble. I’d suggest to give them a look.
