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MrRa [10]
3 years ago
9

Object C has a mass of 3,600 kilograms. Object D has a mass of 900 kilograms. Both objects were placed on different planets so t

hat their weights are equal.
The gravity acting on Object C is ________ times the gravity acting on Object D.

1⁄6
1⁄4
1
4
Physics
1 answer:
FinnZ [79.3K]3 years ago
7 0
The correct answer would be 4
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3 years ago
Please help me to solve this and give me the summary of answer
Neko [114]
Using the principle of floatation.

u = w............(a)

Upthrust of fluid is equal to the weight of the object.

Let the volume of the wood be V.

The upthrust u, is related to the volume submerged in water, and that is 1/5 of it volume, that is (1/5)V = 0.2V

Formula for upthrust, u = vdg

where v = volume of fluid displaced
d = density of fluid
g = acceleration due to gravity

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g = acceleration due to gravity

From (a)

                     u = w

                 vdg =  mg      Cancel out g

                   vd  =  m
 
The v  is equal to 0.2V, which is the submerged volume. Notice that the small letter v is volume of fluid displaced, and capital V is the volume of the solid.

d is density of fluid which is water in this case, 1000 kg/m³

         0.2V * 1000 =  m

           200V =  m

Hence the mass of the object is  200V  kg.

But Density of solid =  Mass of solid / Volume of solid

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Density of solid = 200 kg/m³     
7 0
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1.Which of the following is evidence that the Earth is round?
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Answer:

1\D. Both A and C

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-- If you twisted the peg in the direction that made the string slightly
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