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REY [17]
3 years ago
11

The splitting of water molecule into hydrogen gas and oxygen gas is an example of a

Chemistry
1 answer:
atroni [7]3 years ago
6 0

Answer:

Electrolysis, I hope this helped!

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Balance the following redox equation, identifying the element oxidized and the element reduced. Show all of the work used to sol
Vlad1618 [11]
5HNO₃ + 3P + 2H₂O = 3H₃PO₄ + 5NO

N⁺⁵ + 3e⁻ = N⁺²    5
P⁰ - 5e⁻ = P⁺⁵       3
7 0
3 years ago
Read 2 more answers
Which statement best describes how an electromagnetic motor works?
inn [45]

Answer:

Electrons are moved through a magnet, creating a current. That current interacts with a circuit, moving the conductor in the orientation of the field.

Explanation:

Electro magnetic fields are used to create electric current by the movement of electrons. When a coil of wire is wrapped around a magnet it pushes electrons and they flow through a magnet to create current. This current interacts with circuit to move conductor.

5 0
3 years ago
How many moles of water can be produced from the reaction of 28g of C3H8
Montano1993 [528]
2.55 moles H20 will be produced
7 0
3 years ago
The sun supplies about 1.0 kilowatt of energy for each square meter of surface area (1.0 kW/m^2 where a watt = 1 kJ/s) Plants pr
kaheart [24]

Answer:

0.092 %

Explanation:

The equation of the reaction can be computed as :

12CO_2_{(g)} + 11H_2O_{(l)} \to C_{12}H_{22}O_{11} + 12O_{2_(g)}

\Delta H = 5645 \ kJ

recall that; the number of moles = \dfrac{mass}{molar \ mass}

By applying the method of enthalpy of combustion for sucrose at the same time changing the time from hours to seconds, we can determine the total energy output.

i.e

=\dfrac{0.20g \ of \ sucrose }{m^2 \ 3600 \ s}\times \dfrac{1 \ mol}{342.34 \ g}\times 5.645 kJ/mol

= 9.16 \times 10^{-4} \ kJ/m^2 s

Given that the sun supplies about 1.0 kilowatt, to KJ/m² s, we have:

1.0 \dfrac{kW}{m^2 }= 1.0 \dfrac{kJ}{m^2 s}

Finally, the percentage of sunlight used to produce sucrose :

= \dfrac{9.16 \times 10^{-4} \ kJ/m^2 \ s}{1.0 \ kJ/m^2 . s} \times 100\%

= 0.092 %

6 0
3 years ago
The pH equals the pKa when half of the volume of NaOH necessary to reach the equivalence point has been added. Based on the numb
Elis [28]

Answer:

Half NaOH have been dispensed

Explanation:

Because of the incomplete dissociation of the acid, the reaction is in equilibrium, with an acid dissociation constant, Ka, which is specific to that acid. point are the same. Therefore, at the half-equivalence point, the pH is equal to the pKa.

7 0
3 years ago
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