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REY [17]
3 years ago
11

The splitting of water molecule into hydrogen gas and oxygen gas is an example of a

Chemistry
1 answer:
atroni [7]3 years ago
6 0

Answer:

Electrolysis, I hope this helped!

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To calculate the percentage of people who have a particular allele population studies are conducted to collect data.true or fals
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What is the mass in grams of a single formula unit of silver chloride, AgCI? A) 4.21 x 1021 g B) 8.61 x 10258 C) 1.66 x 10-248 D
bekas [8.4K]

Answer: D) 2.38*10^-^2^2 g

Explanation: The question asks to convert formula unit to grams. It is a unit conversion problem.

1 mole equals to Avogadro number of formula units. So, to convert the given number of formula units to moles, we need to divide by the Avogadro number. After this, we do moles to grams conversion and for this the moles are multiplied by the molar mass of the compound. Molar mass of AgCl is 143.32 gram per mol.

1FormulaUnitAgCl(\frac{1mol}{6.022*10^2^3formulaUnits})(\frac{143.32g}{1mol})

= 2.38*10^-^2^2 g

So, the correct option is D) 2.38*10^-^2^2 g

7 0
3 years ago
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For the following reaction, 0.511 moles of sulfuric acid are mixed with 0.464 moles of zinc hydroxide. What is the formula for t
kkurt [141]

Answer:

Zinc hydroxide, Zn(OH)₂ is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

H₂SO₄ + Zn(OH)₂ —> ZnSO₄ + 2H₂O

From the balanced equation above,

1 mole of H₂SO₄ reacted with 1 mole of Zn(OH)₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of H₂SO₄ reacted with 1 mole of Zn(OH)₂.

Therefore, 0.511 mole of H₂SO₄ will also react with 0.511 mole of Zn(OH)₂.

From the calculation made above, we can see that it will take a higher amount (i.e 0.511 mole) of Zn(OH)₂ than what was given (i.e 0.464 mole) to react completely with 0.511 mole of H₂SO₄.

Therefore, Zn(OH)₂ is the limiting reactant and H₂SO₄ is the excess reactant.

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3 years ago
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<h3>GREETINGS!</h3><h2>_____________________________________</h2><h2><u>Answer</u>:</h2>

N and C

<h2>_____________________________________</h2><h3><u>WHY OPTION A?</u></h3>

Because Lithium and Sodium belong to group 1A whereas Magnesium is from group 2A, which are S block elements and they form ionic bond.

<h2>_____________________________________</h2><h3 /><h3>HOPE IT HELPS!</h3>
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