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2 years ago

13

Miss Sandy is fencing in her rectangular backyard which is 3x^2 feet wide and 4xy + 5x^3 y^2 feet long. Find perimeter of yard H

ow much fencing does she need. Use mathematics to justify your answer

1 answer:

hjlf2 years ago

4 0

Given:

Width of rectangular backyard = $3x^2$ feet

Length of rectangular backyard = $4xy+5x^3y^2$ feet

To find:

The perimeter of yard.

Solution:

Formula or perimeter of a rectangle is

$Perimeter=2(length +width)$

Using this formula, the perimeter of the rectangular backyard is

$Perimeter=2(4xy+5x^3y^2+3x^2)$

$Perimeter=8xy+10x^3y^2+6x^2$

Therefore, the perimeter of the rectangular backyard is $8xy+10x^3y^2+6x^2$ feet. So, $8xy+10x^3y^2+6x^2$ feet fencing is needed.

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Solve for x and explain

galben [10]

Since the two lines are parallel, the angle labeled 130 is congruent to the angle labeled x+ 136 so you can set them equal to each other

130 = x + 136
subtract 136 from both sides

x = -6

4 0

2 years ago

Read 2 more answers

Any help with this greatly appreciated.

Anestetic [448]

Put the equation in standard linear form.

$x'(t) + \dfrac{x(t)}{t + 5} = 5e^{5t}$

Find the integrating factor.

$\mu = \exp\left(\displaystyle \int \frac{dt}{t+5}\right) = e^{\ln|t+5|} = t+5$

Multiply both sides by $\mu$ .

$(t+5) x'(t) + x(t) = 5(t+5)e^{5t}$

Now the left side the derivative of a product,

$\bigg((t+5) x(t)\bigg)' = 5(t+5)e^{5t}$

Integrate both sides.

$(t+5) x(t) = \displaystyle 5 \int (t+5) e^{5t} \, dt$

On the right side, integrate by parts.

$(t+5) x(t) = \dfrac15 (5t+24) e^{5t} + C$

Solve for $x(t)$ .

$\boxed{x(t) = \dfrac{5t+24}{5t+25} e^{5t} + \dfrac C{t+5}}$

3 0

1 year ago

A growth-mindset researcher plans to take an SRS of 200 teenagers from the population of teenagers in North America to see what

Sonbull [250]

Answer:

The mean of the sampling distribution of p is 0.75 and the standard deviation is 0.0306.

Step-by-step explanation:

Central Limit Theorem:

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

75% of teenagers in North America are pursuing a goal they have set for themselves.

This means that $p = 0.75$

Sample of 200.

This means that $n = 200$ .

What are the mean and standard deviation of the sampling distribution of p?

By the Central Limit Theorem

Mean $\mu = p = 0.75$

Standard deviation $s = \sqrt{\frac{0.75*0.25}{200}} = 0.0306$

The mean of the sampling distribution of p is 0.75 and the standard deviation is 0.0306.

4 0

2 years ago

The answer and how to do it.

Kruka [31]

let x = orginal price of the shorts

$21 = x(100%-20%) * 1.05

$21 = x(80%) * 1.05

$21 = 0.8x * 1.05

Subtract 1.05 from both sides

$19.95 = 0.8x

Divide 0.8 from both sides

$24.9375 = x

So the orginal price of the shorts are about $24.94

4 0

3 years ago

Find the area of the

Alex73 [517]

162 m^2

you can make a triangle in the corner with legs length s/2 and the angles are 45 degrees. in a 45 45 90 triangle, the legs are h/sqrt(2) where h is the hypotenuse. this means that s/2=9/2 sqrt(2), s=9 sqrt(2)

and s^2=162

5 0

2 years ago