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Scorpion4ik [409]
3 years ago
8

6)528 What is the answer????

Mathematics
2 answers:
Finger [1]3 years ago
7 0

Answer:

3168

Step-by-step explanation:

Multipy 6  by  528

Hope this Helps :) Pls give <u>Brainliest!</u>

Cloud [144]3 years ago
4 0

Answer:

3168

Step-by-step explanation:

you mean (6)528

so it is 6 times 528=3168

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Which of the following can be used to calculate the volume of water inside the fish bowl?
Lunna [17]

The volume of a sphere can be calculated as

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

r=\frac{AB}{2}=\frac{12}{2}=6

Let's put it into our equation

\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\  \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}

The problem says to use

\pi\approx\frac{22}{7}

Then

V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

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1 year ago
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Scilla [17]

Answer: The first one

6 0
3 years ago
Write an explicit formula for an arithmetic sequence whose common difference is -4.5
makvit [3.9K]
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3 0
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Answer:  From the figure attached,

Point X is the midpoint of line AC.

Since coordinates of the midpoint of the segment joining endpoints  and  is given by,

Therefore, coordinates of the point X will be,  = (a, a)

From triangle AXB,

Length of AB = 2a

Length of AX =  

Length of BX =  

                     =

Length of AX = BX =  

Therefore, triangle AXB is an isosceles triangle.

Step-by-step explanation:

7 0
3 years ago
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How many 2 1⁄4 meter lengths of tape can be cut from 36 meters of tape?
Fed [463]
Answer 16

36/2.25= 16 pieces of rope
6 0
4 years ago
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