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2 years ago

5

______________ are chemicals in the body affecting how you feel.

2 answers:

weeeeeb [17]2 years ago

8 0

Answer:

emotions affect your body and how you feel

7nadin3 [17]2 years ago

3 0

Answer:

emotions

Explanation:

emotions are how you feel and can happen any time

Hope it helps <333

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Didifference between uniform and variable velocity <br>

Simora [160]

Answer:

Uniform velocity is scalar , while variable velocity is vector

Explanation: Uniform velocity and variable velocity is that a body moving with uniform velocity has zero acceleration, while a body that is moving with variable velocity has some acceleration. Uniform velocity is the vector quantity while non-uniform or variable velocity is a scalar quantity

3 0

3 years ago

Read 2 more answers

Saul converts 2.392 hectoliters to liters. What should his new number be? 0.02392 0.2392 239.2 2392

Lelechka [254]

2.392 hector liters is equal to 239.2 liters

4 0

3 years ago

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A thin conducting square plate 1.0 m on the side is given a charge of-2.0 x 10-6 c. A proton is placed 1.0 en above the center o

adell [148]

Answer:

Acceleration, $a=1.08\times 10^{13}\ m/s^2$

Explanation:

It is given that,

Side of the square plate, l = 1 m

Charge on the square plate, $Q=-2\times 10^{-6}\ C$

Position of a proton, x = 1 cm

The electric field due to a parallel plate is given by :

$E=\dfrac{Q}{2A\epsilon_o}$

Electric force is given by :

F = q E

$F=\dfrac{Qe}{2A\epsilon_o}$

e is the charge on electron

The acceleration of the proton can be calculated as :

$a=\dfrac{F}{m}$

m is the mass of proton

$a=\dfrac{Qe}{2A\epsilon_o m}$

$a=\dfrac{2\times 10^{-6}\times 1.6\times 10^{-19}}{2(1)^2\times 8.85\times 10^{-12}\times {1.67\times 10^{-27}}}$

$a=1.08\times 10^{13}\ m/s^2$

So, the acceleration of the proton is $1.08\times 10^{13}\ m/s^2$ . Hence, this is the required solution.

3 0

3 years ago

Sand falls from an overhead bin and accumulates in a conical pile with a radius that is always threethree times its height. Supp

hammer [34]

Answer:

159241.048 cm³/s

Explanation:

r = Radius = 3×height = 3h

h = height = 16 cm

Height of the pile increases at a rate = $\frac{dh}{dt}=22\ cm/s$

$\text{Volume of cone}=\frac{1}{3}\pi r^2h\\\Rightarrow V=\frac{1}{3}\pi (3h)^2h\\\Rightarrow V=3\pi h^3$

Differentiating with respect to time

$\frac{dv}{dt}=9\pi h^2\frac{dh}{dt}\\\Rightarrow \frac{dv}{dt}=9\pi 16^2\times 22\\\Rightarrow \frac{dv}{dt}=159241.048\ cm^3/s$

∴ Rate is the sand leaving the bin at that instant is 159241.048 cm³/s

5 0

3 years ago

(Please help asap)

siniylev [52]

The answer would be B

5 0

3 years ago