Usually, sound needs a medium to travel through, like a vacuum for example.
Light does not need a medium to travel, and since air is considered a medium, light is not dependent on that.
On the other hand, sound needs a medium to travel through, and outer space doesn't contain space, therefore, no sound.
Answer:
The value is 
The direction is into the surface
Explanation:
From the question we are told that
The mass density is 
The coefficient of kinetic friction is 
The current the wire carries is 
Generally the magnetic force acting on the wire is mathematically represented as
Here 
is the frictional force which is mathematically represented as
While 
is the magnetic force which is mathematically represented as
Here 
is the angle between the direction of the force and that of the current
So
So
=> ![B = \mu_k * \frac{m}{L} * [\frac{g}{I} ]](https://tex.z-dn.net/?f=B%20%20%3D%20%20%5Cmu_k%20%2A%20%20%5Cfrac%7Bm%7D%7BL%7D%20%2A%20%5B%5Cfrac%7Bg%7D%7BI%7D%20%5D)
=> ![B = 0.25 * 0.117 * [\frac{9.8}{1.24} ]](https://tex.z-dn.net/?f=B%20%20%3D%20%200.25%20%2A%20%200.117%20%20%2A%20%5B%5Cfrac%7B9.8%7D%7B1.24%7D%20%5D)
=>
Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image
I believe because there is much less air and much more water in the bottom
Tides are incredibly vital. They are controlled by the gravity of the moon pivoting the earth on a 28 day cycle, pulling the water round the world.
On the off chance that you are a mariner you require tide tables for two vital reasons. The first is that the water may not be sufficiently profound to get in and out of harbor or, say, over a sand bank, until specific times of day.
Another reason is that to spare time and power we need to cruise with the active tide on the off chance that it is going our path - to cruise against the tide can mean really going in reverse - I have seen vast cruising vessels beating to windward against the tide on the western ways to deal with the Solent going actually in reverse, (however they had forward speed through the water). Terrible arranging!
Since it is a 28 day cycle and there are 13 heaps of 28 days in a year the tides shift day by day with respect to when it is high tide and low tide, More than that we have neap tides when the highs and lows are less and spring tides when they are most prominent. These rely on upon the periods of the moon.
On the environment front they wash into and through ocean growth circulating air through the plants and ocean life and mix up silt to clean the base of the shoreline and channels and estuaries and invigorate pools that stay on the shoreline for other plant and creature life. This is one justifiable reason motivation behind why tidal hindrances will be a calamity for beach front life since this will be lost to power era. A similar thing applies to wave control and, ashore, wind control - there will be a substantial environmental cost to any maintained or pragmatic utilization of vitality that is in truth not "renewable" - we will upset a fragile adjust of nature that will do much more harm than carbon ever could (on the off chance that it was doing any harm now, which I question)
Tides are not such a great amount of checked as anticipated but rather perilous high tides can happen at the most elevated spring tide, with the twist inland and low gaseous tension - everything pushes the water advance up the shoreline and cause harm and flooding.
Answer: d)
Explanation: In order to justify the answer we have to consider that the energy of photons directely depent on the frequency so the energy is inverselly dependent of the wavelegth.
If both beams have the same power, this means Energy/time so the number of photons per second must be different. As consequence a) is wrong as b) since it is not posible since UV photon have more energy that IR photons. c) It is no necessary know the frequency since the wavelength is related in the form:
c=λν c is the speed of light, λ the wavelegth and ν the frequency.
d) Certainly will be more more IR photons than UV photons to get the same beam power.
