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MArishka [77]
3 years ago
15

How are we able to break wire by repeated bending​

Physics
2 answers:
Arlecino [84]3 years ago
6 0

Answer:

We are able to break it because wire is elastic which means that it stretches. The more we stretch it the more the material comes off.

Explanation:

DIA [1.3K]3 years ago
3 0

Answer:

Repetitive bending cause metal fatigue which is responsible for the break of wire.

Explanation:

Metal fatigue is defined as the weakening of metal when cyclic load is applied on it. Due to metal fatigue cracks are grown in the structure and these cracks become the reason of metal breaking.

Moreover, If the repetitive bending is too fast, heat is produced. This heat changes the structure of atoms in the metal and make it more brittle. That’s why metals break due to repetitive bending.  

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If frequency increases, then wavelength _________.
umka21 [38]

Answer:

Decrease

Explanation:

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3 years ago
If your speed changes from 10 km/h to 6 km/h, you have a(n) ______ acceleration.. a.. negative. c.. neutral. b.. positive. d.. o
photoshop1234 [79]
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5 0
4 years ago
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At one point in the circuit, there is an LED and a resistor in parallel with one another. If you measure the voltage drop across
kifflom [539]

Answer:

C. The voltage drop across the resistor is 2.1V and nothing about the current through the resistor.

Explanation:

When connected in parallel, voltage across the resistances are the same. So if 2.1V was dropped across the LED then 2.1V was also dropped across the resistor. However, this tells us nothing about the current through the resistor. We can find the current across the resistor if we know the resistance of the resistor, but that's about it.

If it were a series connection, then the current would have been the same, but the voltage drop were another story.

7 0
3 years ago
In this lab, you will use a dynamics track to generate collisions between two carts. If momentum is conserved, what variable cha
BartSMP [9]

In collision type of problems since momentum is always conserved

we can say

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

So here along with this equation we also required one more equation for the restitution coefficient

v_{2f} - v_{1f} = e(v_{1i} - v_{2i})

so above two equations are required to find the velocity after collision

here the change in velocity occurs due to the contact force while they contact in each other

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8 0
4 years ago
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A 2MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T.the force on a proton is
Snowcat [4.5K]

Answer:

7.8x10-12N

Explanation:

We know that

Magnetic force = F = qVB

And

Also Kinetic energy K.E is

E = (1/2)mV²

So making v subject

V = √(2E / m)

And

E = KE = 2MeV

= 2 × 106 eV

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= 3.2 × 10–13 J

And then

V= √2x3.2E-13/1.6E-27

1.9E7m/s

Given that

mass of proton = 1.6 × 10–27 kg,

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So F= qBv sinစ

=

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3 years ago
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