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ryzh [129]
3 years ago
14

How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?

Physics
1 answer:
7nadin3 [17]3 years ago
7 0
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

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If we start with 48 g of a radioactive substance with a 2 hour 12 life, how much is left after two half-lives?
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Explanation:

 Half-life is the time taken for a radioactive material to decay to half its original composition:

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   Half- life  = 2hr

 

 After four half lives;

           Initially:                48g

    First halving                24

    Second halving          12

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Answer:

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Since the bar cannot translate, linear momentum is not conserved

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Lo = Lf

I_B*\omega_o+I_b*(V_o/d)=I_B*\omega_f+I_b*(V_f/d)

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I_B =1/3*M_B*L^2

I_b=m_b*d^2

M_B=90/g=9kg; m_b=3kg; d=1.6m; L=3m; V_o=-10m/s; V_f=5m/s; \omega_o=0 rad/s

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\omega_f=m_b*d/I_B*(V_o-V_f)

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\omega_f=-2.6rad/s

Since the bar can only rotate (it canno translate), only angular momentum is conserved.

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