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ryzh [129]
3 years ago
14

How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?

Physics
1 answer:
7nadin3 [17]3 years ago
7 0
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

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Density = mass / volume ;
1 Cubic Centimeter = 0,000001 Cubic Meter
8 cm^3 = 0.000008 m^3
12,9 g = 0,0129 kg


The density is 0,0129 kg/ 0,000008 m^3 = <span><u>1612,5 kg/m^3</u> </span>
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Answer:

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A plane flying at 70.0 m/s suddenly stalls. If the acceleration during the stall is 9.8 m/s2 directly downward, the stall lasts
tino4ka555 [31]

Answer:

v = 66.4 m/s

Explanation:

As we know that plane is moving initially at speed of

v = 70 m/s

now we have

v_x = 70 cos25

v_x = 63.44 m/s

v_y = 70 sin25

v_y = 29.6 m/s

now in Y direction we can use kinematics

v_y = v_i + at

v_y = 29.6 - (9.81 \times 5)

v_y = -19.5 m/s

since there is no acceleration in x direction so here in x direction velocity remains the same

so we will have

v = \sqrt{v_x^2 + v_y^2}

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v = 66.4 m/s

4 0
2 years ago
Tsunamis are fast-moving waves often generated by underwater earthquakes. In the deep ocean their amplitude is barely noticable,
vovangra [49]

Answer:

v =163.95 m/s

Explanation:

Given that,

The wavelength of wave, \lambda=646\ km=646\times 10^3\ m

Distance covered, d=3630\ km=3630\times 10^3\ m

We need to find the speed of the wave. We know that,

speed = distance/time

So,

v=\dfrac{3630\times 10^3\ m}{22140\ s}\\\\=163.95\ m/s

So, the speed of the wave is equal to 163.95 m/s.

6 0
2 years ago
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