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ryzh [129]
3 years ago
14

How long does it take (in minutes) for light to reach venus from the sun, a distance of 1.152 × 108 km?

Physics
1 answer:
7nadin3 [17]3 years ago
7 0
Using the precise speed of light in a vacuum (299,792,458 \ \frac{m}{s}), and your given distance of 1.152 * 10^{8} km, we can convert and cancel units to find the answer. The distance in m, using \frac{1000 \ m}{1 \ km}, is 1.152 * 10^{11} m. Next, for the speed of light, we convert from s to min, using \frac{1 \ min}{60 \ s}, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is 6.405 min.

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Answer:

(a) dime

Explanation:

Convert all to metric unit:

0.5 cm = 0.005 m

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In order to find out we would need to calculate the ratio R between the object diameter d and their distance s to our eyes:

R_m = \frac{d_m}{s_m} = \frac{3.48*10^6}{3.85*10^8} \approx 0.009

R_p = \frac{d_p}{s_p} = \frac{0.005}{0.71} \approx 0.007

R_d = \frac{d_d}{s_d} = \frac{0.018}{0.71} \approx 0.0253

Since the ratio of the dime is larger than the ratio of the moon, and the ratio of the pea is smaller than the ratio of the moon, only the (a) dime can cover your view of the moon.

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3 years ago
Will give correct answer brainliest
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200 \times 80\%

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Answer:

1.57772 m

Explanation:

M = Mass of actor = 84.5 kg

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v = Velocity of costar

V  = Velocity of actor

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As the energy of the system is conserved

\frac{1}{2}MV^2=Mgh_i\\\Rightarrow V=\sqrt{2gh_i}\\\Rightarrow V=\sqrt{2\times 9.81\times 4.3}\\\Rightarrow V=9.18509\ m/s

As the linear momentum is conserved

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Applying conservation of energy again

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