Question

a 90 gram object moves around a circle whose diameter is 2.56 m at a constant speed off 16 m/s. what is the object acceleration? how much time will take to complete the around?

Answer 1

Answer:

$a=200\ m/s^2$ and t = 0.5 s

Explanation:

Given that,

Mass of the object, m = 90 gram = 0.09 kg

Diameter of the circle, d = 2.56 m

Radius, r = 1.28 m

Speed, v = 16 m/s

We need to find the object acceleration. On the circular path, acceleration is given by :

$a=\dfrac{v^2}{r}\\\\a=\dfrac{(16)^2}{1.28}\\\\a=200\ m/s^2$

So, the object's acceleration is $200\ m/s^2$.

Let t is time it will take to complete the around. Speed is given by :

$v=\dfrac{2\pi r}{t}\\\\t=\dfrac{2\pi r}{v}\\\\t=\dfrac{2\pi \times 1.28}{16}\\\\t=0.5\ s$

So, time to cover one complete round is 0.5 s.