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cupoosta [38]
3 years ago
7

The gas that a diver breathes must be maintained at a partial pressure of 0.20 atm of oxygen. More oxygen could poison the diver

, and less would lead to suffocation. The total pressure, however, must be equal to the external pressure to avoid collapsing the lungs. A special valve is used to equalize the pressure inside the diver's lungs with the external pressure by adding helium gas. The valve also maintains oxygen levels by using Dalton's Law. If the total pressure in the cylinder is 1.00 atm, what is the pressure of the helium?
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
5 0

<u>Answer:</u> The partial pressure of helium gas is 0.80 atm

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the partial pressure of helium gas, we use the law given by Dalton, which is:

P_T=p_{He}+p_{O_2}

We are given:

Total pressure of the cylinder, P_T = 1.00 atm

Vapor pressure of oxygen gas, p_{O_2} = 0.20 atm

Putting values in above equation, we get:

1.00=p_{He}+0.20\\\\p_{He}=1.00-0.20=0.80atm

Hence, the partial pressure of helium gas is 0.80 atm

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Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

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