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Ipatiy [6.2K]
3 years ago
12

One star might appear brighter than another star because

Physics
1 answer:
Marrrta [24]3 years ago
4 0

Answer:

A star's brightness also depends on its proximity to us. The more distant an object is, the dimmer it appears. Therefore, if two stars have the same level of brightness, but one is farther away, the closer star will appear brighter than the more distant star - even though they are equally bright!

Can I have brainliest?

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Why is the milky way galaxy not expanding together with the rest of the universe?
tamaranim1 [39]
Because it on by it's self floating around not forming part of something

8 0
4 years ago
A bungee jumper of mass 75kg is attached to a bungee cord of length L=35m. She walks off a platform (with no initial speed), reac
attashe74 [19]

Answer:

1. 77.31 N/m

2. 26.2 m/s

3. increase

Explanation:

1. According to the law of energy conservation, when she jumps from the bridge to the point of maximum stretch, her potential energy would be converted to elastics energy. Her kinetic energy at both of those points are 0 as speed at those points are 0.

Let g = 9.8 m/s2. And the point where the bungee ropes are stretched to maximum be ground 0 for potential energy. We have the following energy conservation equation

E_P = E_E

mgh = kx^2/2

where m = 75 kg is the mass of the jumper, h = 72 m is the vertical height from the jumping point to the lowest point, k (N/m) is the spring constant and x = 72 - 35 = 37 m is the length that the cord is stretched

75*9.8*72 = 37^2k/2

k = (75*9.8*72*2)/37^2 = 77.31 N/m

2. At 35 m below the platform, the cord isn't stretched, so there isn't any elastics energy, only potential energy converted to kinetics energy. This time let's use the 35m point as ground 0 for potential energy

mv^2/2 = mgH

where H = 35m this time due to the height difference between the jumping point and the point 35m below the platform

v^2/2 = gH

v = \sqrt{2gH} = \sqrt{2*9.8*35} = 26.2 m/s

3. If she jumps from her platform with a velocity, then her starting kinetic energy is no longer 0. The energy conservation equation would then be

E_P + E_k = E_E

So the elastics energy would increase, which would lengthen the maximum displacement of the cord

5 0
4 years ago
Which acceleration graph corresponds to the pressure graph shown?
elixir [45]

Answer:

Graph D

Explanation:

6 0
3 years ago
You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As
34kurt

Your position at time t, relative to the stop line:

x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t

The Porsche's position:

x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2

a. You pass the Porsche immediately after the time it takes for x_1=x_2:

-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s

at which point you both will have traveled 7.8 m from the stop line.

b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about t=4.4\,\rm s, at which point you both will have traveled 29 m.

c. At time t, the Porsche is moving at velocity

v=\left(3\dfrac{\rm m}{\mathrm s^2}\right)t

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.

6 0
4 years ago
Which statement describes an essential characteristic of data in an experiment?
MAVERICK [17]
The whole of the data that you have researched on
3 0
4 years ago
Read 2 more answers
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