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Oksi-84 [34.3K]
2 years ago
14

Find the mass of a sample that has a dersity of 2 g/mL and a volume of 10 mL

Physics
1 answer:
In-s [12.5K]2 years ago
4 0

Answer:

mass = volume x density.

Explanation:

2 x 10 = 20g

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Which sphere of Earth is associated with plate tectonics?
Marrrta [24]

When looking at this question, we can easily start by eliminating certain answers. In the selections you've provided, you've shown atmosphere. We can easily eliminate letter A, as that makes absolutely no sense. Moving on, you also eliminate letter B, as that deals with ecosystems and whatnot. And finally, you can eliminate hydrosphere, letter C - as that's not the same. That deals with water, like oceans or rivers.

That leaves you with D) Lithosphere for your answer. The Lithosphere is the rigid part of the earth, the outermost layer, I would say. The crust / mantle. That's why it would be letter D - plate tectonics seem to have relations with the Lithosphere. The lithosphere is affected.

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A wire with a resistance R is lengthened to 3.07 times its original length by pulling it through a small hole. Find the new resi
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Explanation:

Below is an attachment containing the solution.

4 0
3 years ago
Calculate the net force on particle q1. First, find the direction of the force particle q2 is exerting on particle q1. Is it pus
ValentinkaMS [17]

The net force on particle particle q1 is 13.06 N towards the left.

<h3>Force on q1 due to q2</h3>

F(12) = kq₁q₂/r₂

F(12) = (9 x 10⁹ x 13 x 10⁻⁶ x 7.7 x 10⁻⁶)/(0.25²)

F(12) = -14.41 N  (towards left)

<h3>Force on q1 due to q3</h3>

F(13) = (9 x 10⁹ x 7.7 x 10⁻⁶ x 5.9 x 10⁻⁶)/(0.55²)

F(13) = 1.352 N (towards right)

<h3>Net force on q1</h3>

F(net) = 1.352 N - 14.41 N

F(net) = -13.06 N

Thus, the net force on particle particle q1 is 13.06 N towards the left.

Learn more about force here: brainly.com/question/12970081

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8 0
2 years ago
An electron follows a helical path in a uniform magnetic field of magnitude 0.340 T. The pitch of the path is 6.00 µm, and the m
dedylja [7]

Answer:

The electron's speed is 34007.35 m/s

Explanation:

It is given that,

Magnetic field, B = 0.34 T

Magnetic force on the electron, F=1.85\times 10^{-15}\ N

The electron follows a helical path. We have to find the speed of an electron. The formula for magnetic force is given by :

F=B\times q\times v

q = charge on an electron, q=1.6\times 10^{-19}\ C

v = velocity of an electron

v=\dfrac{F}{Bq}

v=\dfrac{1.85\times 10^{-15}\ N}{0.34\ T\times 1.6\times 10^{-19}\ C}

v = 34007.35 m/s

Hence, this is the required solution.

4 0
3 years ago
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