On a distance-time graph, what is shown when the curve is flat going from left to the right?

Convert 1 second into solar day.

otez555 [7]

DIVIDE 1 BY 86400 TO CONVERT 1 SECOND INTO SOLAR DAY.

6 0

3 years ago

A runner is jogging in a straight line at a

Fiesta28 [93]

Answer:

Total distance traveled by bird is 10.5 km.

Explanation:

Given that,

Velocity of runner= 8.4 km/hr

Distance = 6.3 km

Velocity of bird = 42 km/hr

Suppose, How far does the bird travel?

We need to calculate the time of bird

Using formula of time

$t=\dfrac{d}{v_{b}}$

Put the value into the formula

$t=\dfrac{6.3}{42}$

$t=0.15\ hr$

We need to calculate the distance runner travels during time period

Using formula of distance

$d=v_{r}\times t$

$d=8.4\times0.15$

$d=1.26\ km$

We need to calculate the distance of runner to FL

Using distance

$d'=6.3-1.26$

$d'=5.04\ km$

We need to calculate the net closing speed between runner and bird

Using speed

$v'=v_{r}+v_{b}$

$v'=8.4+42$

$v'=50.4\ km/hr$

We need to calculate the time for runner and bird to meet

Using formula of time

$t=\dfrac{d}{v'}$

Put the value into the formula

$t=\dfrac{5.04}{50.4}$

$t=0.1\ hr$

We need to calculate the distance covered by runner

Using formula of distance

$d=vt$

Put the value into the formula

$d=8.4\times0.1$

$d=0.84\ km$

We need to calculate the distance covered by bird to runner

Using formula of distance

$d=vt$

Put the value into the formula

$d=42\times0.1$

$d=4.2\ km$

We need to calculate the total distance

Using distance

$D=6.3+4.2$

$D=10.5\ km$

Hence, Total distance traveled by bird is 10.5 km.

4 0

3 years ago

Why sky appear blue

NikAS [45]

Thus, as sunlight of all colors passes through air, the blue part causes charged particles to oscillate faster than does the red part. ... More of the sunlight entering the atmosphere is blue than violet, however, and our eyes are somewhat more sensitive to blue light than to violet light, so the sky appears blue.Apr 7, 2003

5 0

3 years ago

A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distancer1

Jobisdone [24]

Answer:

The magnitude of the electric field in the second case will be $\frac{1}{8}$ of the electric field in the first case

Explanation:

The electric field at a distance $r_1$ < R from the center of the sphere is given by

the formula $E_1$ = $\frac{kQr_1}{R^3}$

where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.

It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance $r_1$ from the center.

In the second case the electric field will be given by

$E_2$ = $\frac{kQr_1}{(2R)^3} = \frac{kQr_1}{8R^3} =\frac{1}{8} \frac{kQr_1}{R^3} = \frac{1}{8} E_1$

Therefore the magnitude of the electric field in the second case will be $\frac{1}{8}$ of the electric field in the first case.

4 0

4 years ago

Which statement is true if the mass of object A is twice that of object B?

Contact [7]

Answer:

b is the answer

Explanation:

8 0

3 years ago