Answer:
384.6 m
Explanation:
The length of the runway airport should be long enough to accommodate the aircraft during its acceleration from rest to 161 km/h at rate of 2.6 m/s. We can use the following equation of motion to solve for this:
where v0 = 0 m/s is the initial velocity of the airplane when it start accelerating, v = 161 km/h = 161*1000*(1/60)(1/60) = 44.72 m/s is the airborn speed, a = 2.6 m/s2 is the acceleration, and is the distance of the runway, which we care looking for
Answer:
voltage across = 1.6 V
Explanation:
given data
resistance R = 57.61 Ω
capacitance c = 13.13 mF = 13.13 × F
inductance L = 196.03 mH = 0.19603 H
fixed rms output Vrms = 23.86 V
to find out
voltage across circuit
solution
we know resonant frequency that is
resonant frequency = 1 / ( 2π√(LC)
put the value
resonant frequency = 1 / ( 2π√(0.19603×13.13 ×)
resonant frequency f = 3.1370 HZ
so current will be at this resonant is
current = Vrms / R
current = 23.86 / 57.61
current = 0.4141 A
and
so voltage across will be
voltage across = current / ( 2π f C )
voltage across = 0.4141 / ( 2π ( 3.1370) 13.13 × )
voltage across = 1.6 V