Question

How many grams are in 3.01 x 1024 molecules of H2SO4

Answer 1

Answer:

490. g H₂SO₄

General Formulas and Concepts:

Chemistry - Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis
• Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

3.01 × 10²⁴ molecules H₂SO₄

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

Step 3: Convert

$3.01 \cdot 10^{24} \ molecules \ H_2SO_4(\frac{1 \ mol \ H_2SO_4}{6.022 \cdot 10^{23} \ molecules \ H_2SO_4} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} )$ = 490.287 g H₂SO₄

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

490.287 g H₂SO₄ ≈ 490. g H₂SO₄