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prisoha [69]
3 years ago
12

A set of charged plates 0.00262 m apart has an electric field of 155 N/C between them. What is the potential difference between

the plates? V
Physics
1 answer:
mylen [45]3 years ago
5 0

Answer: The potential difference between the plates = 0.4061V

Explanation:

Given that the

Electric field strength E = 155 N/C

Distance d = 0.00262 m

From the definition of electric field strength, is the ratio of potential difference V to the distance between the plates. That is

E = V/d

Substitute E and d into the above formula

155 = V/0.00262

Cross multiply

V = 155 × 0.00262

V = 0.4061 V

The potential difference between the plates is 0.4061 V

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madam [21]
The kinetic energy of an object of mass m moving with speed v is given by:
K= \frac{1}{2}mv^2
For the bicycle in our problem, m=10 kg and v=2 m/s, so the kinetic energy is
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4 0
3 years ago
How much potential energy foes a 5kg mass have when its 2 meters above the ground?(Hint :PE=m*g*h)​
frez [133]

Answer:

<h2>98 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

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Hope this helps you

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2 years ago
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6 0
3 years ago
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oksano4ka [1.4K]

Answer:

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A

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