This is also called a plum-pudding model of an atom which has positive charges spread throughout a spherical figure with electrons embedded uniformly within its background.
Hope this answers your question! :)
Answer:
option A
Explanation:
Given,
wavelength of light,![\lambda = 560\ nm](https://tex.z-dn.net/?f=%20%5Clambda%20%3D%20560%5C%20nm)
refractive index of gasoline, n₁ = 1.40
Refractive index of water, n₂ = 1.33
thickness of the film, t = ?
Condition of constructive interference is given by
![2 n t = (m+\dfrac{1}{2})\lambda](https://tex.z-dn.net/?f=2%20n%20t%20%3D%20%28m%2B%5Cdfrac%7B1%7D%7B2%7D%29%5Clambda)
For minimum thickness of the film m = 0
From the question we can clearly observe that phase change from gasoline to air
so, n = 1.4
![2 \times 1.4 \times t = \dfrac{560}{2}](https://tex.z-dn.net/?f=2%20%5Ctimes%201.4%20%5Ctimes%20t%20%3D%20%5Cdfrac%7B560%7D%7B2%7D)
![t = 100\ nm](https://tex.z-dn.net/?f=%20t%20%3D%20100%5C%20nm)
Hence, the correct answer is option A
The constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
<h3> Constant angular acceleration</h3>
Apply the following kinematic equation;
ωf² = ωi² - 2αθ
where;
- ωf is the final angular velocity when the centrifuge stops = 0
- ωi is the initial angular velocity
- θ is angular displacement
- α is angular acceleration
ωi = 3400 rev/min x 2π rad/rev x 1 min/60s = 356.05 rad/s
θ = 52 rev x 2π rad/rev = 326.7 rad
0 = ωi² - 2αθ
α = ωi²/2θ
α = ( 356.05²) / (2 x 326.7)
α = 194.02 rad/s²
Thus, the constant angular acceleration (in rad/s2) of the centrifuge is 194.02 rad/s².
Learn more about angular acceleration here: brainly.com/question/25129606
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I would say that the apmosphere would change and we probley would die that's my guess
<span> Maths delivers! Braking distance ... If the </span>car<span> is initially travelling at u</span>m<span>/s, then the stopping distance d </span>m<span> ... the </span>speed<span> of the </span>car<span> at the </span>instant<span> the </span>brakes<span> are applied. ... An object with </span>constant acceleration<span> travels the </span>same<span> distance as it would ... We </span>start<span> with the second equation of motion:.</span>