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3 years ago

Find the number of grams 4.00 moles of CU(CN)2

Chemistry

1 answer:

USPshnik [31]3 years ago

4 0

Answer:

462g

Explanation:

First, let us calculate the molar mass of Cu(CN)2. This is illustrated below:

Molar Mass of Cu(CN)2 = 63.5 + 2(12+14) = 63.5 + 2(26) = 63.5 + 52 = 115.5g/mol

Number of mole of Cu(CN)2 given from the question = 4moles

Mass = number of mole x molar Mass

Mass of Cu(CN)2 = 4 x 115.5

Mass of Cu(CN)2 = 462g

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Based on the stoichiometry of the reaction, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

<h3>What is stoichiometry of a reaction?</h3>

The stoichiometry of a reaction is the molar ratio in which reactants combine to form products.

The stoichiometry of the reaction shows that 6 moles of copper (i) nitrate produces 2 moles of aluminium nitrate.

molar mass of Copper(I) nitrate, CuNO3 = 126 g

molar mass of aluminum nitrate, Al(NO3)3 = 213 g

88.0 g of aluminum nitrate, Al(NO3)3 = 88.0/213 moles = 0.413 moles

0.413 moles of Al(NO3)3 will be produced by 0.413 ×6/3 = 1.239 moles of CuNO3

Mass of 1.239 moles of CuNO3 = 1.239 × 126 = 156.114 g of CuNO3

Therefore, 156.114 g of CuNO3 are required to produce 88.0 grams of aluminum nitrate, Al(NO3)3.

Learn more about stoichiometry at: brainly.com/question/16060223

Therefore, 156.114 g of CuNO3

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Find the number of grams 4.00 moles of CU(CN)2 ​

Find the number of grams 4.00 moles of CU(CN)2