Answer:
It is known generally that polar compounds are soluble in polar solvents. Based on the structure of benzoic acid, it comprises the non-polar C6H6 group and polar COOH group. Based on the structure, in benzoic acid, the nonpolar hydrocarbon outweighs and influences the polar part as nonpolar, due to which benzoic acid is not soluble in water.
On the other hand, benzoic acid produces sodium salt benzoic acid when it reacts with 2.5 M sodium hydroxide, this salt is ionic. Generally, the ionic compounds are soluble in water. Therefore, the salt of benzoic acid gets dissolved in water. Hence, benzoic acid is soluble in the solution of sodium hydroxide.
It is highly reactive and when it is kept in open it does react with the oxygen present in the surroundings and burns therefore it is kept immersed in kerosene and please thank me and if you need more comment
The empirical formula is Ca₃P₂O₈.
<em>Assume</em> that you have 100 g of the compound.
Then you have 38.76 g Ca, 19.97 g P, and 41.28 g O.
Now, we must convert these <em>masses to moles</em> and <em>find their ratio</em>s.
If the number in the ratio are not close to integers, you <em>multiply them by a numbe</em>r that makes them close to integers.
From here on, I like to summarize the calculations in a table.
<u>Element</u> <u>Mass/g</u> <u> Moles </u> <u> </u><u>Ratio </u> <u> ×2 </u> <u>Integers</u>
Ca 38.76 0.967 07 1.4998 2.9995 3
P 19.97 0.644 82 1 2 2
O 41.28 2.580 0 4.0011 8.0023 8
The empirical formula is Ca₃P₂O₈.
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