Question

An object increases its velocity from 22 m/s to 36 m/s in 5s.what is the acceleration of the object

Answer 1

Answer:

2.8 m/s²

Explanation:

v=v0+at <=> 36 = 22 + a×5 <=> 5a = 36-22 <=> 5a = 14 <=> a = 14/5 <=>

<=> a = 2.8 m/s²

Answer 2

A :-) for this question , we should apply
a = v - u by t
Given - u = 22 m/s
v = 36 m/s
t = 5 sec
Solution -
a = v - u by t
a = 36 - 22 by 5
a = 14 by 5
a = 2.8 m/s^2

.:. The acceleration is 2.8 m/s^2.