I think the answer would be C
Given :
A rope 6m long is fixed at one end, the other end is attached to a light string so that it is free to move.
The speed of waves on the rope is 18 m/s.
To Find :
The frequency of the second harmonic.
Solution :
We know, for second harmonic wave :
Wavelength = Length of rope

Now, we know frequency is given by :

Therefore, the frequency of the second harmonic is 3 s⁻¹.
Answer:
<em>speed of the alpha particle is 2 x 10^7 m/s.</em>
Explanation:
energy of alpha particle = 8.3 Mev
1 Mev = 1.602 x 10^-13 J
8.3 Mev = 
solving,
= 8.3 x 1.602 x 10^-13 = 1.329 x 10^-12 J
mass of a alpha particle = 6.645 x 10^−27 kg
The energy of the alpha particle is the kinetic energy KE of the alpha particle
KE = 
where m is the mass of the alpha particle
v is the velocity of the alpha particle
substituting values, we have
1.329 x 10^-12 = 
= 4 x 10^14
= <em>2 x 10^7 m/s</em>
Slow down significantly before the curve in the road
Answer:
mass x velocity
Explanation:
The momentum of an object is the product of its mass and velocity;
Momentum = mass x velocity
Mass is the quantity of matter in a body
Velocity is the rate of change of displacement with time.
Also, momentum is used to quantify the particular amount of motion a body can give.