Answer:
1. Wf= 627.9 J
2. Wg= 416.32J
3. Work done by normal force = 0 always
4. Wk = 192.3J
5. Wt = 19.28 J
Explanation:
The question have no questions specific so here some possible questions:
1) Calculate the work done on the suitcase by the force F
2) Calculate the work done on the suitcase by the gravitational force.
3) Calculate the work done on the suitcase by the normal force.
4) Calculate the work done on the suitcase by the friction force.
5) Calculate the total work done on the suitcase.
1)
work = F * d
Wf= 161N * 3.90m
Wf= 627.9 J
2)
work = mgh
Wg= 20kg*9.8m/s² * 3.9m*sin33º
Wg= 416.32J
3)
Work done by normal force = 0 always
4)
friction work = µmgdcosΘ
Wk = 0.30*20kg* 9.8m/s²*3.90m*cos33º
Wk = 192.3J
5)
total work = (627.9- 416.32- 192.3) J
Wt = 19.28 J
Opposite charges attract; like charges repel :)
Answer:
Explanation:
006
They are acting in opposite directions. Therefore the net force is found by subtraction. The sign is the same as the larger number.
Net Force = 99.6 - 52.8 = 46.8 N acting in the same direction as the 99.6 which is upward.
008
If the two forces act in the same direction, the net force is found by addition.
Net Force = 99.6 + 52.8 = 152.4 N downward.
The top box is cell and I’ll look at the others
