Answer:
The width of the slit is 0.167 mm
Explanation:
Wavelength of light,
Distance from screen to slit, D = 88.5 cm = 0.885 m
The distance on the screen between the fifth order minimum and the central maximum is 1.61 cm, y = 1.61 cm = 0.0161 m
We need to find the width of the slit. The formula for the distance on the screen between the fifth order minimum and the central maximum is :
where
a = width of the slit
a = 0.000167 m
a = 0.167 mm
So, the width of the slit is 0.167 mm. Hence, this is the required solution.
plasmas are a lot like gases
hope this helps.
Answer:
1. Golf ball is in the range of only particulate detectable range
2, alpha partcle is in ultraviolet range of wavelength
3.bullet is in xray range of wavelength
All in the EMW spectrum
Answer:
They break off large ice sheets found at the North and South poles.