Answer:
45.873 KN/mL is the ultimate bearing capacity of the foundation.
Explanation:
C' = 10.0 kN/m², Ф' = 25, r = 18 kN/m²
ration of Df/B ≤ 1 , Df ≤ B (1 ≤ 2.5m)
It is a shallow foundation
∴ Ultimate bearing Capacity
qu = C' + r
.
+
Br
NФ = tan²(45 + Ф/2)
= tan²(45 - 25/2)
= 0.41
Nq = NФ×e^(πtanФ') = 0.41e^(πtan25)
= 1.756
Nr = 1.8tanФ(Nq - 1) = 1.8tan25(1.756 - 1)
= 0.634
Nc = 1.621
putting the above values in equation.
qu = 45.873 KN/mL
Solution :
Given :
Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa
The phase diagram is provided below.
a). The phase is a standard mixture.
b). At pressure, p = 200 kPa, T =
Temperature = 120.21°C
c). Specific volume
d). Specific energy ()
e). Specific enthalpy
At
f). Enthalpy at m = 0.5 kg
= 1022.91 kJ
