Question

A 2.5 m wide rough continuous foundation is placed in the ground at 1 m depth. There is bedrock present at 1 m depth below the bottom of the foundation. The soil properties are c9 5 10.0 kN/m2 , f9 5 258, and g 5 18.0 kN/m3 . Determine the ultimate bearing capacity of the foundation.

Answer 1

Answer:

45.873 KN/mL is the ultimate bearing capacity of the foundation.

Explanation:

C' = 10.0 kN/m²,  Ф' = 25,  r = 18 kN/m²

ration of Df/B ≤ 1 ,   Df ≤ B (1 ≤ 2.5m)

It is a shallow foundation

∴ Ultimate bearing Capacity

qu = C'$N_c$ + r$D_F$.$N_q$ + $\frac{1}{2}$Br$N_r$

NФ = tan²(45 + Ф/2)

      = tan²(45 - 25/2)

      = 0.41

Nq = NФ×e^(πtanФ') = 0.41e^(πtan25)

     = 1.756

Nr = 1.8tanФ(Nq - 1) = 1.8tan25(1.756 - 1)

    = 0.634

Nc = 1.621

putting the above values in equation.

qu = 45.873 KN/mL