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Alexxandr [17]
3 years ago
14

Capitol Brewing Inc.'s management is very concerned with declining sales of their major product, a dark ale, and has asked for h

elp understanding the reasons. The most appropriate way to begin is with
Engineering
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

Exploratory research

Explanation:

This is research used to investigate a problem which is not clearly defined. It intended to establish priorities, develop operational solutions and then implementation. This research is conducted to have a better understanding of the existing problem and ensures that definite conclusions are drawn to solve the problem of declining sales. Capitol Brewing Inc.'s management should be ready to implement recommended solutions after the research.

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An elevation is.... * 10 points a. A detailed description of requirements, composition and materials for a proposed building. b.
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Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

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Why would an aerospace engineer limit the maximum angle of deflection of the control surfaces?
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Answer:

You can create high drag which allows a steeper angle without increasing your air speed on landing. you can reduce the length of landing role. Flaps are also used to increase the drag they are retracted when they are not needed. it is adviseable to down he flaps during the time of take off.

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3 years ago
can anyone give me tips on adding HP to my 2014 dodge charger SE? it uses the 3.6L220 CI 24 valve v6 vvt (variable valve timing)
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5 0
2 years ago
Consider unsteady fully developed Coutte flow between two infinite parallel plates. This problem involves the following paramete
FrozenT [24]

Answer:

Option (C) = 4 is correct.

Explanation:

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6 0
3 years ago
In a production facility, 3 cm thick large brass plates (k = 110 W/mC, α = 33.9 × 10-6 m2 /s) that are initially at a uniform
zysi [14]

Answer:

Explanation:

Given.

Thickness of brass plate t = 3 cm

Thermal conductivity of brass k = 110 W/m.°C

Density of brass \rho = 8530 kg/m^3

Specific heat of brass C_p =380J/kg.°C

Thermal diffusivity of brass \alpha = 33.9\times 10^{-6} m^2/s

Temperature of oven T_{\infty} = 700°C

The initial temperature T_i= 25°C

Plate remain in the oven t =10 min  

Heat conduction in the plate is one-dimensional since the plate is large relative to its thickness  and there is thermal symmetry about the center plane.

The thermal properties of the plate are constant.

The heat transfer coefficient is constant and uniform over the entire surface.

The Fourier number is > 0.2 so that the one-term approximate solutions (or the transient  temperature charts) are applicable (this assumption will be verified).

The Biot number for this process Bi = \frac{hL}{k}\\\\Bi=\frac{(80 W/m^2.°C)(0.015 m)}{(110 W/m.°C)}\\=Bi =0.0109

The constants \lambda_1 and A_1 corresponding to this Biot are, from 11-2 tables.

The interpolation method used to find the

\lambda_1=0.1039  and A_1=1.0018&#10;  

The Fourier number \tau=\frac{\alpha t}{L^2}\\\\\tau=\frac{(33.9\times 10^{-6} m^2/s)(10 min \times 60 s/min)}{(0.015m)^2}&#10;\\\\\tau=90.4>0.2

Therefore, the one-term approximate solution (or the transient temperature charts) is applicable.

Then the temperature at the surface of the plates becomes

\theta(L,t)_{wall}=\frac{T(x,t)-T_{\infty}}{(T_i-T_{\infty})}\\\\\theta(L,t)_{wall}=A_1e^{-\lambda_1^2\tau}\cos(\lambda_1L/L)\\\\\theta(L,t)_{wall}=(1.0018)e^{-(0.1039^2(90.4))}\cos(0.1039)\\\\\theta(L,t)_{wall}=0.378\\\\\frac{T(L,t)-700}{25-700}=0.378\\\\T(L,t)=445°C

3 0
2 years ago
Read 2 more answers
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