Answer:
12.7m/s
Explanation:
Given parameters:
Mass of the diver = 77kg
Height = 8.18m
Unknown:
Speed of the diver before hitting the water = ?
Solution:
The speed of the diver before hitting the water is the final velocity.
To solve this problem, we use the expression below;
v² = u² + 2gH
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
H is the height
Now insert the parameters and solve;
v² = 0² + 2 x 9.8 x 8.18
v² = 160.328
v = 12.7m/s
Answer:
Explanation:
Given
mass of box is m
speed of box is v
coefficient of friction 
Box is moving at a constant speed i.e. Net Force on box is zero
i.e. Frictional Force and Force Applied are Equal
The Rate at which power is generated is
<h3><u>Given </u><u>:</u><u>-</u></h3>
- The mass of the body is doubled
- The height of the body is constant
<h3><u>Solution </u><u>:</u><u>-</u><u> </u></h3>
We know that ,
Potential energy = mgh
<u>Therefore</u><u>, </u>
We can say that,
PE is directly proportional to Mass of the body
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
PE of the body = 2m * g * h. ...eq( I)
From (I) , we can conclude that, If mass of the body get doubled then its PE will also be doubled .
