A.is an example of decomposition reaction. 
        
             
        
        
        
<span>The mechanical advantage to simple machines is that they allow a decreased input force to create a larger output force.
<span>TRUE</span></span>
        
             
        
        
        
Answer:
I'm pretty sure it's 20m/s because 1300m divided by 65 seconds is 20 so I think it's 20m/s
Explanation:
 
        
             
        
        
        
Answer:  
the required revolution per hour is 28.6849
Explanation: 
Given the data in the question;
we know that the expression for the linear acceleration in terms of angular velocity is;
 = rω²
 = rω²
ω² =  / r
 / r
ω = √(  / r )
 / r )
where r is the radius of the cylinder
ω is the angular velocity
given that; the centripetal acceleration equal to the acceleration of gravity a  = g = 9.8 m/s²
  = g = 9.8 m/s²
so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m
Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m
so we substitute
ω = √( 9.8 m/s² / 3909.87 m )
ω = √0.002506477 s²  
ω = 0.0500647 ≈ 0.05 rad/s   
we know that; 1 rad/s = 9.5493 revolution per minute
ω = 0.05 × 9.5493 RPM 
ω = 0.478082 RPM   
1 rpm = 60 rph  
so   
ω = 0.478082 × 60
ω = 28.6849  revolutions per hour  
Therefore, the required revolution per hour is 28.6849
 
        
             
        
        
        
We need to see what forces act on the box:
In the x direction:
Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.
In the y direction:
N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 
From N-Gcosα=0 we get: 
N=Gcosα, we will need this for the force of friction.
Now to solve for Fh:
Fh=ma + Ff + Gsinα, 
Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²
Fh=ma + μmgcosα+mgsinα
Now we plug in the numbers and get:
Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N
The horizontal force for pulling the body up the ramp needs to be Fh=71 N.