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777dan777 [17]
3 years ago
15

A car of mass m accelerates from speed v1 to speed v2 while going up a slope that makes an angle θ with the horizontal. The coef

ficient of static friction is μs, and the acceleration due to gravity is g. Find the total work W done on the car by the external forces. Express your answer in terms of the given quantities. You may or may not use all of them.
Physics
1 answer:
nlexa [21]3 years ago
7 0

Answer:

The answer is W=\frac{1}{2} m (v_2^{2} -v_1^{2} )

Explanation:

Here you have to take into account the theorem of work and energy.  This theorem says that the total work done by external forces on a body is used to modify the kinetic energy. So the only thing you have to do is determine the kinetic energy in the initial (K_1) and final moment (K_2), then the diference between them is the amount of net work that act over the body.

K_1=\frac{1}{2} m v_1^{2}

K_2=\frac{1}{2} m v_2^{2}

W=K_2-K_1=\frac{1}{2} m v_2^{2} - \frac{1}{2} m v_1^{2}=\frac{1}{2} m (v_2^{2} -v_1^{2} )

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Answer:

g_n=\dfrac{2}{9}g

Explanation:

M = Mass of Earth

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On new planet

g_n=\dfrac{G2M}{(3R)^2}\\\Rightarrow g_n=\dfrac{2GM}{9R^2}

Dividing the two equations we get

\dfrac{g_n}{g}=\dfrac{\dfrac{2GM}{9R^2}}{\dfrac{GM}{R^2}}\\\Rightarrow \dfrac{g_n}{g}=\dfrac{2}{9}\\\Rightarrow g_n=\dfrac{2}{9}g

The acceleration due to gravity on the other planet is g_n=\dfrac{2}{9}g

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Answer:

The film thickness is 4.32 * 10^-6 m

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Here in this question, we are interested in calculating the thickness of the film.

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