Answer:
Weaker attraction between its molecules than the green substance. It's molecules now move away from each other.
Explanation:
Liquid to gas.
London dispersion
dipole-dipole
<span>because it is a pattern; airgo cycle</span>
N₂+3H₂⇒ 2NH₃
m(NH₃)=1250+225*2=1700 grams
N₂ is the limiting <span>reagent.
1250 grams are</span><span> left when the maximum amount of ammonia is formed.</span>
Answer:
18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
Explanation:
Mercury oxide has molar mass of 216.6 g/ mol. It gas a molecular formula of HgO.
The decomposition of mercury oxide is given by the chemical equation below:
2HgO ----> 2Hg + O₂
2 moles of HgO decomposes to produce 1 mole of Hg
2 moles of HgO has a mass of 433.2 g
433.2 g of HgO produces 216.6 g of Hg
18.0 of HgO will produce 18 × 216.6/433.2 g of Hg = 9.0 g of Hg
Therefore, 18.0 g of mercury (11) oxide decomposes to produce 9.0 grams of mercury
