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Olegator [25]
3 years ago
6

A skydiver reaches terminal velocity. Then he opens his parachute.

Physics
2 answers:
schepotkina [342]3 years ago
4 0

Answer:

it is 0.9999.10896

Explanation:

MatroZZZ [7]3 years ago
4 0

Answer:

Explanation:

Remark

He's pulled upwards by the parachute. The formula is given below. Details are found   searching for terminal velocity.

V_t=\sqrt\frac{2mg}{\rho A C_d}

Whatever that calculation turns out to be, a person has to be going a whole lot slower before he can safely hit the ground. The parachute is designed so that the person will be slowed very quickly to a safe velocity so when he hits the ground the impulse will not be as great as it could be. The force that the parachute delivers acts upward and opposes the force of gravity which is a downward force.

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I think its an echo?
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5 0
3 years ago
24 grams of magnesium metal reacts with 16 grams of oxygen gas to form magnesium oxide. according to the law of conservation of
wariber [46]

The mass of magnesium oxide must be 40 grams

Explanation:

The law of conservation of mass states that the total mass of the reactant in a chemical reaction must be equal to the total mass of the products after the reaction has completed.

In this problem, we have:

Reactants:

Magnesium metal (mass: 24 grams)

Oxygen gas (mass: 16 grams)

Products:

Magnesium oxide (mass: ?)

According to the law of conservation of mass, the mass of the magnesium oxide must be equal to the sum of the mass of the magnesium metal and the oxygen gass. Therefore:

Mass (magnesium oxide) = 24 g + 16 g = 40 g

Learn more about law of conservation of mass:

brainly.com/question/5017646

#LearnwithBrainly

8 0
3 years ago
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