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Ede4ka [16]
1 year ago
15

Photoelectrons with a maximum speed of 8.00 • 106 m/sec are ejected froma surface in the presence of light with a frequency of 6

.32 · 1014Hz. If themass of an electron is 9.10 . 10-31 kg, calculate the maximum kineticenergy of a single electron, in joules.a. 3.64 x 10-24 Jb. 2.88 x 10-16 Jc. 5.82 x 10-17 Jd. 2.91 x 10-17 J
Physics
1 answer:
Andru [333]1 year ago
5 0

The kinetic energy is given by:

K=\frac{1}{2}mv^2

We know the mass and the maximum speed, plugging their values in the expression above we have:

\begin{gathered} K=\frac{1}{2}(9.1\times10^{-31})(8\times10^6)^2 \\ K=2.91\times10^{-17}\text{ J} \end{gathered}

Therefore, the answer is d.

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A 25 kg child is riding on a swing. If the child travels 8.9 m/s at the bottom of their swing, how high into the air is the chil
Setler [38]

Answer:

h = 4.04 m

Explanation:

Given that,

Mass of a child, m = 25 kg

The speed of the child at the bottom of the swing is 8.9 m/s

We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,

mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}

Put all the values,

h=\dfrac{(8.9)^2}{2\times 9.8}\\\\h=4.04\ m

So, the child is able to go at a height of 4.04 m.

7 0
2 years ago
What is the weight of a 5.00 kg object on Earth? Assume g=9.81 m/s^2.
Softa [21]

<em>weight = (mass) x (gravity)</em>

Weight = (5.00 kg) x (9.81 m/s²)

weight = (5.00 x 9.81) (kg-m/s²)

<em>Weight = 49.05 Newton</em>

7 0
3 years ago
Is this right?? please help me. IT IS SOCIOLOGY!!
Westkost [7]

Answer:

Yes, it is correct : )

Explanation:

Hope this helps!

8 0
2 years ago
Read 2 more answers
Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hour
Serhud [2]
For the answer to the question above, first find out the gradient. 

<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>

<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>

<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>

<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>

<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
4 0
3 years ago
A radio wave has a frequency of 5.5 × 104 hertz and travels at a speed of 3.0 × 108 meters/second. What is its wavelength
Ne4ueva [31]
Use v=fλ
3x10^8=5.5x 10^4 λ
λ=5.45x10^3m
4 0
3 years ago
Read 2 more answers
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