Answer:
-767,2kJ
Explanation:
It is possible to sum enthalpies of half-reactions to obtain the enthalpy of a global reaction using Hess's law. For the reactions:
1) H₂(g) + ¹/₂O₂(g) ⟶ H₂O(g) ΔH₁= −241.8 kJ
2) X(s) + 2Cl₂(g) ⟶ XCl₄(s) ΔH₂= +361.7 kJ
3) ¹/₂H₂(g) + ¹/₂Cl₂(g) ⟶ HCl (g) ΔH₃= −92.3 kJ
4) X(s) + O₂(g) ⟶ XO₂(s) ΔH₄= − 607.9 kJ
5) H₂O(g) ⟶ H₂O(l) ΔH₅= − 44.0 kJ
The sum of (4) - (2) produce:
6) XCl₄(s) + O₂(g) ⟶ XO₂(s) + 2Cl₂(g) ΔH₆ = ΔH₄ - ΔH₂ = -969,6 kJ
(6) + 4×(3):
7) XCl₄(s) + 2H₂(g) + O₂(g) ⟶ XO₂(s) + 4HCl(g) ΔH₇ = ΔH₆ + 4ΔH₃= -1338,8 kJ
(7) - 2×(1):
8) XCl₄(s) + 2H₂O(g) ⟶ XO₂(s) + 4HCl(g) ΔH₈ = ΔH₇ - 2ΔH₁= -855,2kJ
(8) - 2×(5):
9) XCl₄(s) + 2H₂O(l) ⟶ XO₂(s) + 4HCl(g) ΔH₉ = ΔH₈ - 2ΔH₅= <em>-767,2kJ</em>
I hope it helps!
Answer:
1.47 atm
Explanation:
Step 1: Calculate the moles corresponding to 41.6 g of oxygen
The molar mass of oxygen is 32.00 g/mol.
41.6 g × 1 mol/32.00 g = 1.30 mol
Step 2: Convert 30.0 °C to Kelvin
We will use the following expression.
K = °C + 273.15 = 30.0 + 273.15 = 303.2 K
Step 3: Calculate the pressure exerted by the oxygen
We will use the ideal gas equation.
P × V = n × R × T
P = n × R × T / V
P = 1.30 mol × (0.0821 atm.L/mol.L) × 303.2 K / 22.0 L = 1.47 atm
The chemical balanced equation for the given question is this:
2AL[NO3]3 + 3CaO = AL2O3 + 3Ca[NO3]2.
So, one of the product formed is AI2O3. The other product is Ca[NO3]2.
The reaction is a double replacement reaction.
Get an equal amount of each element by adding coefficients to the different compounds.
