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Margarita [4]
3 years ago
15

When sufficient quantity of heat has been added to reach the boiling point of a solution, what happens to any additional heat ad

ded?
a) additional heat is used to maintain the boiling of the liquid as the process is endothermic and requires continued input of energyb) additional heat raises the temperature of the liquid which in turn increases the at which boiling occursc) additional heat lowers the intermolecular forces of the liquid which in turn increases the volatility of the liquidd) additional heat alters the vicosity and the surface tension of the liquid which raises the vapor pressure and increases the boiling point which is why you must continually heat the solutione) none of the above are correct statements
Chemistry
1 answer:
Daniel [21]3 years ago
8 0

Answer:

d) additional heat alters the vicosity and the surface tension of the liquid which raises the vapor pressure and increases the boiling point which is why you must continually heat the solution

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What is the volume of 4.00 moles of CO2 gas at STP?
likoan [24]

Answer:

89.6L

Explanation:

1mole of any gas occupies 22.4L. This simply means that,

1mole of CO2 occupies 22.4L at stp.

Therefore, 4moles of CO2 will occupy = 4 x 22.4 = 89.6L

8 0
3 years ago
Select the correct answer from each drop-down menu.
stealth61 [152]

Answer:

Light energy; chemical

Explanation:

The light energy of the Sun is converted into chemical energy by the plants.

5 0
3 years ago
(a) the temperature on a warm summer day is 87 °f. what is the temperature in °c? (b) many scientific data are reported at 25
olchik [2.2K]

Answers:

              (a)  30.55 °C

              (b) 298 K and 77°F

              (c)  204.44 °C and 477.44 K

              (d)  -320.8 °F and -196 °C

Explanation:

Converting °C into °F;

                                   °F  =  °C × 1.8 + 32

Converting °F into °C;

                                   °C  =  °F - 32 ÷ 1,8

Converting °C into K;

                                   K  =  °C + 273

Converting K into °C;

                                   °C  =  K - 273

8 0
3 years ago
Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon
Pani-rosa [81]

<u>Answer:</u> The ratio of carbon in both the compounds is 1 : 2

<u>Explanation:</u>

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: Cu_2O\text{ and }CuO

  • <u>For Sample 1:</u>

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = \frac{2.26}{2.26}=1

For Oxygen  = \frac{4.55}{2.26}=2.01\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is CO_2

  • <u>For Sample 2:</u>

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = \frac{3.57}{3.57}=1

For Oxygen  = \frac{3.57}{3.57}=1

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is CO

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = \frac{1}{2}\times 1=\frac{1}{2}

Now, taking the ratio of carbon atoms in both the samples, we get:

C_1:C_2=\frac{1}{2}:1=1:2

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0
2 years ago
**PLEASE ANSWER QUICK, I'LL GIVE BRAINLIEST TO THE RIGHT ANSWER !!**
rewona [7]

Answer:

c

Explanation:

the correct answer would be answer c

6 0
2 years ago
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