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Margarita [4]
2 years ago
15

When sufficient quantity of heat has been added to reach the boiling point of a solution, what happens to any additional heat ad

ded?
a) additional heat is used to maintain the boiling of the liquid as the process is endothermic and requires continued input of energyb) additional heat raises the temperature of the liquid which in turn increases the at which boiling occursc) additional heat lowers the intermolecular forces of the liquid which in turn increases the volatility of the liquidd) additional heat alters the vicosity and the surface tension of the liquid which raises the vapor pressure and increases the boiling point which is why you must continually heat the solutione) none of the above are correct statements
Chemistry
1 answer:
Daniel [21]2 years ago
8 0

Answer:

d) additional heat alters the vicosity and the surface tension of the liquid which raises the vapor pressure and increases the boiling point which is why you must continually heat the solution

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The formula equation below represents a _________ reaction. CaO (s) H2O (l) → Ca(OH)2(l)
myrzilka [38]
The first one is a synthesis reaction (A + B --> AB)
Second one is a double displacement (AB + CD --> AD + CB)
Third one is a synthesis
Fourth one is a single displacement (A + BC --> B + AC)
The fifth one is a decomposition (AB --> A + B). This is a reverse of synthesis.
6 0
3 years ago
Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrate
Phoenix [80]

The question is incomplete , complete question is :

Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrated (undiluted) standard solution for which you measured the absorbance. Use 3 significant figures. Molarity (μmol/L) =31.5

Given: [TZ] = 0.5461 mol/L

Answer:

The concentration of TZ solution in μmol/L is 546 μmol/L

Explanation:

Molarity of the TZ solution = 0.5461 mol/L

This means that 0.5461 moles of TZ are present in 1 L of solution.

Moles of TZ = 0.5461 mol

mol= 1000 \mu mol

0.5461 mol=0.5461\times 1000 \mu mol=546.1 \mu mol

So, the concentration of TZ solution in μmol/L is :

546.1 μmol/L ≈ 546 μmol/L

7 0
2 years ago
The first-order rate constant for the decomposition of N2O5:
kifflom [539]

Answer:

0.0055 mol of N2O5 will remay after 7 min.

Explanation:

The reaction follows a first-order.

Let the concentration of N2O5 after 7 min be y

Rate = Ky = change in concentration of N2O5/time

K is rate constant = 6.82×10^-3 s^-1

Initial concentration of N2O5 = number of moles/volume = 2.1×10^-2/1.8 = 0.0117 M

Change in concentration = 0.0117 - y

Time = 7 min = 7×60 = 420 s

6.82×10^-3y = 0.0117 - y/420

0.0117 - y = 420×6.82×10^-3y

0.0117 - y = 2.8644y

0.0117 = 2.8644y + y

0.0117 = 3.8644y

y = 0.0117/3.8644 = 0.00303 M

Number of moles of N2O5 left = y × volume = 0.00303 × 1.8 = 0.0055 mol (to 2 significant digits)

5 0
3 years ago
Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction free energy of the following chemical
julia-pushkina [17]

Answer:

43.0 kJ

Explanation:

The free energy (ΔG) measures the total energy that is presented in a thermodynamic system that is available to produce useful work, especially at thermal machines. In a reaction, the value of the variation of it indicates if the process is spontaneous or nonspontaneous because the free energy intends to decrease, so, if ΔG < 0, the reaction is spontaneous.

The standard value is measured at 25°C, 298 K, and the value of free energy varies with the temperature. It can be calculated by the standard-free energy of formation (G°f), and will be:

ΔG = ∑n*G°f products - ∑n*G°f reactants, where n is the coefficient of the substance in the balanced reaction.

By the balanced reaction given:

2NOCl(g) --> 2NO(g) + Cl2(g)

At ALEKS Data tab:

G°f, NOCl(g) = 66.1 kJ/mol

G°f, NO(g) = 87.6 kJ/mol

G°f, Cl2(g) = 0 kJ/mol

ΔG = 2*87.6 - 2*66.1

ΔG = 43.0 kJ

6 0
3 years ago
Can you help me please
den301095 [7]
Type in the Eye lins it will help
4 0
2 years ago
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