South America's major mineral resources are gold, silver, copper, iron ore, tin, and petroleum. These resources found in South America have brought high income to its countries especially in times of war or of rapid economic growth by industrialized countries elsewhere.
Answer: Dmitri Mendeleev was a Russian chemist who lived from 1834 to 1907. He is considered to be the most important contributor to the development of the periodic table. His version of the periodic table organized elements into rows according to their atomic mass and into columns based on chemical and physical properties
Answer:
4.81×10¹⁰ atoms.
Explanation:
We'll begin by converting 3.2 pg to Ca to grams (g). This can be obtained as follow:
1 pg = 1×10¯¹² g
Therefore,
3.2 pg = 3.2 pg × 1×10¯¹² g / 1 pg
3.2 pg = 3.2×10¯¹² g
Therefore, 3.2 pg is equivalent to 3.2×10¯¹² g
Next, we shall determine the number of mole in 3.2×10¯¹² g of Ca. This can be obtained as follow:
Mass of Ca = 3.2×10¯¹² g
Molar mass of Ca = 40.08 g/mol
Mole of ca=.?
Mole = mass /molar mass
Mole of Ca = 3.2×10¯¹² / 40.08
Mole of Ca = 7.98×10¯¹⁴ mole.
Finally, we shall determine the number of atoms present in 7.98×10¯¹⁴ mole of Ca. This can be obtained as illustrated below:
From Avogadro's hypothesis,
1 mole of Ca contains 6.02×10²³ atoms.
Therefore, 7.98×10¯¹⁴ mole of Ca will contain = 7.98×10¯¹⁴ × 6.02×10²³ = 4.81×10¹⁰ atoms.
Therefore, 3.2 pg of Ca contains 4.81×10¹⁰ atoms.
Answer:
See explanation
Explanation:
Step 1: Data given
For the reaction aA + bB ⇆ cC + dD
Kc = [C]^c * [D]^d / [A]^a [B]^b
a. SbCl5(g) ⇄ SbCl3(g) + Cl2(g)
Kc = [Cl2]*[SbCl3] / [SbCl5]
b. 2 BrNO(g) ⇄ 2NO(g) + Br2(g)
Kc = [Br2]*[NO]² / [BrNO]²
c. CH4(g) + 2 H2S(g) ⇄ CS2(g) + 4 H2(g)
Kc = [H2]^41 * [CS2] / [H2S]²*[CH4]
d. 2CO(g) + O2(g) ⇄ 2CO2(g)
Kc = [CO2]² / [O2][CO]²
Answer:
How many grams of CCL4 were formed? 116.9 g
How many grams of Cl2 reacted with the CH4? 243.8 g
Explanation:
First we need to know the molar mass for every element or compound in the reaction:
Now we proceed to calculate the amount of moles produced, per product:
To calculate the mass of chlorine we just need to make a mass balance:
