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2 years ago

Solutions of aluminum nitrate and sodium sulfate react to form sodium nitrate and aluminum sulfate. Classify this reaction.

Chemistry

2 answers:

nadya68 [22]2 years ago

8 0

Answer:

Double replacement.

Explanation:

In the given reaction, there is not synthesis of compound.

The decomposition reactions are those in which a compound dissociates into simpler molecules or ions.

So the given reaction is not decomposition even.

In single replacement reactions, there is replacement of one group from a compound to other compound or element or ion.

Here two groups are being replaced (sulfate and nitrate) so the given reaction will be classified as double replacement.

JulijaS [17]2 years ago

5 0

2 Al(NO₃)₃ + 3 Na₂SO₄ = Al₂(SO₄)₃ + 6 NaNO₃

Aluminium Nitrate + Salt Cake = Aluminium Sulfate + Sodium Nitrate

Answer D ( double replacement )

hope this helps!

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How many atoms are there in 5K2CO3

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Answer:

Depends on what are you refering to

Explanation:

So depending on what you are looking for (your question is quite vauge)

there are 5 atoms of the comopound (K2CO3)

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5, 15, or 25.

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2 years ago

How many significant figures are in the number 020.310

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Answer:

Explanation:

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What does the peak of a probability curve for an electron in an atom indicate?

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The distance from the nucleus at which the electron is most likely to be found

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3 years ago

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A sample of a compound contains 41.33 g of carbon and 8.67 g of hydrogen. The molar mass of the

mihalych1998 [28]

Answer:

C6H15

Explanation:

First, we calculate the empirical formula as follows:

C = 41.33 g

H = 8.67 g

We convert each mass value to mole by dividing each element by its molar mass (C = 12g/mol, H = 1g/mol)

C = 41.33g ÷ 12g/mol = 3.44mol

H = 8.67g ÷ 1g/mol = 8.67mol

Next, we divide each mole value by the smallest (3.44mol)

C = 3.44mol ÷ 3.44mol = 1

H = 8.67mol ÷ 3.44mol = 2.52

We multiply this ratio by 2 to get a simple whole number ratio

C = 1 × 2 = 2

H = 2.52 × 2 = 5.04

Based on this, the whole number ratio of C and H is 2:5, hence, the empirical formula is C2H5.

The molecular mass of the compound is given as 87.18 g/mol, hence, the molecular formula is calculated as follows:

(C2H5)n = 87.18

[12(2) + 1(5)]n = 87.18

[24 + 5]n = 87.18

(29)n = 87.18

n = 87.18 ÷ 29

n = 3.006

Approximately to whole number, n = 3

Hence, the molecular formula of the compound is [C2H5]3

= C6H15

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2 years ago

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Answer:

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