All categories

2 years ago

A student draws the model shown below. Which of these best compares the conditions at Location X and Location Y?

Chemistry

1 answer:

arlik [135]2 years ago

5 0

Answer:

Explanation:

You have to use formula b to your answer

You might be interested in

Why does knowing types of mixtures help you to identify a substance?

Reil [10]

Answer:

This is my own explanation:

Explanation:

It is important to know the mixtures you input together because you may determine the type of substance you produced from different elements and several combinations of matter. This assists in identifying your specific substance.

8 0

2 years ago

How does carbonation affect melting point

FromTheMoon [43]

The sodium in soda lowers the melting point and makes the ice melt more slowly than it would in plain water because with the addition of any substance, there are fewer free water molecules available to form bonds together and freeze

3 0

6 months ago

When an aqueous solution of silver nitrate is

Andre45 [30]

Answer:

$K^{+}$ and $NO_{3}^{-}$

Explanation:

The equation for the reaction is AgNO3(aq) + KCl(aq) ==> AgCl(s) + KNO3(aq)

With all the ions, it is

$Ag^{+}$ (aq) + $NO_{3} ^{-}$ (aq) + $K^{+}$ (aq) + $Cl^{-}$ (aq) ==> AgCl(s) +

$K^{+}$ and $NO_{3} ^{-}$ do not change, so they are the spectator ions and are removed

The ionic equation is:

$Ag^{+}$ (aq) + $Cl^{-}$ (aq) ==> AgCl(s)

8 0

2 years ago

An ore is to be analyzed for its iron content by an oxidation-reduction titration with permanganate ion. A 4.230 g sample of the

Leya [2.2K]

Answer:

See explanation

Explanation:

The balanced redox reaction equation is;

8H+ + MnO4^- + 5Fe2+ ---------> Mn2+ + 5Fe3+ + 4H2O

Amount of KMnO4 reacted = 31.60/1000 * 0.05120 = 1.62 * 10^-3 moles

From the reaction equation;

1 mole of MnO4^- reacted with 5 moles of Fe2+

1.62 * 10^-3 moles will react with 1.62 * 10^-3 moles * 5/1 = 8.1 * 10^-3 moles

Mass of Fe2+ reacted = 8.1 * 10^-3 moles * 56 g/mol

Mass of Fe2+ reacted = 0.45 g

Amount of iron in the sample = 0.45 g

Percentage of iron in the sample;

0.45 g/4.230 g * 100 = 10.6 %

8 0

2 years ago

the chloride of a metal M contains 47.25% of metal 1.0 gram of metal would be displaced from a compound by 0.88 gram of another

GenaCL600 [577]

Answer:

The equivalent weight of M is approximately 31.8 g

The equivalent weight of N is approximately 27.98 g

Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

Where by the chemical formula for the metal chloride is MClₓ, we have;

47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

$\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}$

0.4725 × (W + 35.5·x) = W

0.4725·W + 0.4725×35.5×x = W

W - 0.4725·W = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

7 0

2 years ago