what symbol would be included in the noble gas notation for an element that had valence electrons in the 5s sub shell

Chemistry

1 answer:

horsena [70]3 years ago

6 0

Answer:

The answer is Kr (Krypton).

This is because krypton has an electronic configuration of:

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

Taking note of the sequence of electronic configuration:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s

It can be seen that Kyrpton's electronic configuration finishes just before the 5s subshell. Therefore, the noble gas notation for an element with valence electrons in the 5s subshell can use [Kr] as a shortcut to denote its electronic configuration. For example:

If an element has 1 valence electron in the 5s subshell, the noble gas notation will be:

[Kr] 5s1

Explanation:

You might be interested in

Mendeleev created this table as he noticed that a

Nimfa-mama [501]

Answer:

Mendeleev had left the noble gases out of his periodic table.

Explanation:

Mendeleev's periodic table is pictured in the image attached to the question.

Mendeleev's table obviously lacked the noble gases. The reason for this grave omission is simple; the noble gases were not known as at the time when he formulated his periodic table. There weren't any known elements whose properties were similar to the properties of the noble gases. This would have lead him to suspect their existence.

4 0

2 years ago

A sample of nitrogen gas has the temperature drop from 250.°c to 150.°c at constant pressure. what is the final volume if the in

Leviafan [203]

Charles law gives the relationship between temperature of gas and volume of gas.
It states that for a fixed amount of gas, temperature is directly proportional to volume of gas.
V / T = k
where V- volume , T - temperature and k - constant
$\frac{V1}{T1} = \frac{V2}{T2}$
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation.
T1 = 250 °C + 273 = 523 K
T2 = 150 °C + 273 = 423 K
Substituting the values in the equation,

$\frac{310 mL}{523 K} = \frac{V}{423K}$
V = 251 mL
the new volume is 251 mL

6 0

3 years ago

A sample of helium gas is heated from 20.0°C to 40.0°C. This

Montano1993 [528]

Answer:

C. 548mL

Explanation:

Attached is an image of the explanation. Hope this helps!