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Artist 52 [7]
3 years ago
9

what symbol would be included in the noble gas notation for an element that had valence electrons in the 5s sub shell

Chemistry
1 answer:
horsena [70]3 years ago
6 0

Answer:

The answer is Kr (Krypton).

This is because krypton has an electronic configuration of:

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

Taking note of the sequence of electronic configuration:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s

It can be seen that Kyrpton's electronic configuration finishes just before the 5s subshell. Therefore, the noble gas notation for an element with valence electrons in the 5s subshell can use [Kr] as a shortcut to denote its electronic configuration. For example:

If an element has 1 valence electron in the 5s subshell, the noble gas notation will be:

[Kr] 5s1

Explanation:

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Answer:

Reaction 1 is balanced but 2 is not balanced , the balance equation are :

1. CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)

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Explanation:

Balanced Equations : These are the equation which follows the law of conservation of mass .

The total number of atoms present in reactant is equal to total number of atoms present in product.

1. CH_{3}COOH(aq) + NaHCO_{3}(aq)\rightarrow CO_{2}(g) + H_{2}O(l) + CH_{3}COONa(aq)

This is acid - base type reaction where

CH_{3}COOH(aq) act as Acid

NaHCO_{3}(aq) act as weak base

Reactant :CH_{3}COOH(aq) ,NaHCO_{3}

Number of atoms of :

C = 2 (CH_{3}COOH(aq)) + 1 (NaHCO_{3})

   = 2 + 1

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H  = 4(CH_{3}COOH(aq)) + 1 (NaHCO_{3})

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O = 2(CH_{3}COOH(aq)) + 3 (NaHCO_{3})

    = 5

Na = 1 (NaHCO_{3})

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Product :  CO_{2}(g),H_{2}O(l) , CH_{3}COONa(aq)

Number of atoms :

C = 1(CO_{2}(g)) + 2(CH_{3}COONa(aq))

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H = 2(H_{2}O(l)) + 3(CH_{3}COONa(aq))

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O = 1(H_{2}O(l)) + 2(CH_{3}COONa(aq))

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    = 1 + 2 + 2

    = 5

Na = 1(CH_{3}COONa(aq)

     = 1

Number of Na =1 , C = 3 , H= 5 and O =5 in both reactant and product , so it is a balanced reaction

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Check the balancing in both reactant and products should be :

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